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Doss [256]
3 years ago
10

A program evaluator wanted to know if a combination of experience and education gave leadership candidates an advantage in meeti

ng job performance standards better than experience alone, or education alone. There were a total of 39 candidates who had both experience and education, and 200 candidates who had either experience or education. Of the candidates who had both experience and education, 21 met the standards, while 18 did not meet the standards. Of the candidates who had only experience or education, 100 met the standards, and 100 did not meet the standards.
Select the correct statistical test to determine if there is a relationship between preparation and meeting the standards, calculate the results, and communicate the results.
a. None of the choices are correct.
b. A Spearman rs is the best choice. The test reveals that there is a strong correlation between preparation and meeting the standards (rs = [237] = 1.00, p <.05). This means there is a relationship between the variables.
c. A chi-square test would be the best choice for examining observed data. The results are significant, (X- [1, N = 239] = 0.19, p<.05). This means that there was a relationship between preparation and meeting the standards, we reject the null hypothesis that the variables are independent.
d. A chi-square test would be the best choice for examining observed data. The results are not significant (X4 [1, N = 239] = 0.19, p > .05). This means that there was not a relationship between preparation and meeting the standards, we retain the null hypothesis that the variables are independent.
Mathematics
1 answer:
DochEvi [55]3 years ago
6 0

Answer:

pol

Step-by-step explanation:

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$80 decreased by 20%
padilas [110]

Answer:

$64

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Surveyors wished to know the distance across a lake between A and B. They measured the distance from B to C as 100 m and the ang
kherson [118]

Answer:

<h3>AB ≈ 70m</h3>

Step-by-step explanation:

Check the attachment for the diagram.

You can see from the diagram that it is a right angled triangle with opposite side AB and adjacent side BC. Using SOH, CAH, TOA trig identity to get the length of AB. According to TOA;

tan 35° = opposite/adjacent

tan 35° = AB/BC

tan 35° = AB/100

AB = 100tan35°

AB = 100 * 0.7002

AB = 70.02m

Hence the distance across a lake between A and B is approximately 70m

5 0
3 years ago
Simplify the expression -3/(-2/5)
Annette [7]

-3/(-2/5) = -3 * (5/-2)=15/2=7.5

5 0
3 years ago
Read 2 more answers
Unit sales for new product ABC have varied in the first seven months of this year as follows: Month Jan Feb Mar Apr May Jun Jul
Alecsey [184]

Answer:

\sigma = 121.53

Step-by-step explanation:

Required

The population standard deviation

First, calculate the population mean

\mu = \frac{\sum x}{n}

This gives:

\mu = \frac{148+ 329+ 491 +167+ 228+285+ 441}{7}

\mu = \frac{2089}{7}

\mu = 298.43

The population standard deviation is:

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}

So, we have:

\sigma = \sqrt{\frac{(148 - 298.43)^2 + ..........+ (441- 298.43)^2}{7}}

\sigma = \sqrt{\frac{103387.7143}{7}}

\sigma = \sqrt{14769.6734714}

\sigma = 121.53

8 0
3 years ago
Which statements best describe the dot plot or box plot ? Check all that apply.Need answer ASAP
zloy xaker [14]
<h3>The 2 answers are: A and D</h3>

==========================================

Explanations

A. True. This is because there are 13 dots shown. You cannot use the box plot to determine this.

B. False. This contradicts choice A above. Also, we cannot use the box plot to determine how many people there are. What 12-7 = 5 is showing is that the range is 5. This means the range for the age of runners is 5 years. In other words, 5 years is the span from the youngest (age 7) to the oldest (age 12).

C. False. The median is 10 as its shown in the box plot. Recall the median for any box and whisker plot is the vertical line inside the box.

D. True. The vertical line inside the box is the median. This vertical line does not have to be exactly halfway between the left and right edges of the box.

E. False. A box plot can be used to determine variability (in terms of range and IQR). You can determine the variability from a dot plot, though you'll have to do a bit of work to get it.

F. False. Refer to choice E.

3 0
4 years ago
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