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Doss [256]
3 years ago
10

A program evaluator wanted to know if a combination of experience and education gave leadership candidates an advantage in meeti

ng job performance standards better than experience alone, or education alone. There were a total of 39 candidates who had both experience and education, and 200 candidates who had either experience or education. Of the candidates who had both experience and education, 21 met the standards, while 18 did not meet the standards. Of the candidates who had only experience or education, 100 met the standards, and 100 did not meet the standards.
Select the correct statistical test to determine if there is a relationship between preparation and meeting the standards, calculate the results, and communicate the results.
a. None of the choices are correct.
b. A Spearman rs is the best choice. The test reveals that there is a strong correlation between preparation and meeting the standards (rs = [237] = 1.00, p <.05). This means there is a relationship between the variables.
c. A chi-square test would be the best choice for examining observed data. The results are significant, (X- [1, N = 239] = 0.19, p<.05). This means that there was a relationship between preparation and meeting the standards, we reject the null hypothesis that the variables are independent.
d. A chi-square test would be the best choice for examining observed data. The results are not significant (X4 [1, N = 239] = 0.19, p > .05). This means that there was not a relationship between preparation and meeting the standards, we retain the null hypothesis that the variables are independent.
Mathematics
1 answer:
DochEvi [55]3 years ago
6 0

Answer:

pol

Step-by-step explanation:

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Find the line y=a+bx which best approximates the data points
Vika [28.1K]

Answer:

y = 11.84x - 32.71

Step-by-step explanation:

Here, the given data points,

(−3,−70),(−1,−42),(1,−21),(2,−9),(4,14),

Let x represents the input value and y represents the output value,

So, the table that represents the given situation is,

x         -3            -1             1             2             4

y       -70          -42         -21         -9             14

By the above table,

\sum x=3

\sum y=-128

\sum xy = 269

\sum x^2=31

\sum y^2 = 7382

Let the equation of the line is,

y = bx + a

Where,

a=\frac{\sum y \sum x^2 - \sum x\sum xy}{n(\sum x^2)-(sum x)^2}

b=\frac{n\sum xy - \sum x \sumy}{n(\sum x^2)-(\sum x)^2}

n = number of data points = 5,

By substituting the values we get,

a = - 32.70547945 ≈ - 32.71,

b = 11.84246575 ≈ 11.84,

Hence, the equation of line would be,

y = 11.84x - 32.71

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3 years ago
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Step-by-step explanation:

C. in descending order by weight<br /><br />

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I keep forgetting the process for this: 3(x^2 + 5)(x^2 - 5) Can someone help?
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Answer:

see explanation

Step-by-step explanation:

Note that (x² + 5)(x² - 5) are the factors of a difference of squares

a² - b²  = (a + b)(a - b)

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kondor19780726 [428]

Answer:

Step-by-step explanation:

(1) = f(x) = 4x

y = 4x\\x = 4y\\y = \frac{x}{4}\\f^{-1}(x) = \frac{x}{4}

(2) h(x) = x + 4

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Replace x with y and vice versa:

x = y + 4

And then solve for 'y':

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5 0
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