How to calculate 1/2 × 24cm²

If g(x) =x^2 + 1, find g(4)

Papessa [141]

Answer:

17

Step-by-step explanation:

Since we are evaluating g(x) for g(4), we would substitute x in the equation with 4.

x² + 1

(4)²+ 1

16 + 1

17

I hope this helps

4 0

2 years ago

Solve the equation to find the value of m and n. 2m + 3n = -5 5m + 3n = 1

Leokris [45]

Answer:

m = 2, n = - 3

Step-by-step explanation:

Given the 2 equations

2m + 3n = - 5 → (1)

5m + 3n = 1 → (2)

Subtract (2) from (1) term by term to eliminate n

2m - 5m = - 5 - 1

- 3m = - 6 ( divide both sides by - 3 )

m = 2

Substitute m = 2 into either of the 2 equations and solve for n

Substituting into (1)

2(2) + 3n = - 5

4 + 3n = - 5 ( subtract 4 from both sides )

3n = - 9 ( divide both sides by 3 )

n = - 3

3 0

3 years ago

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A quadrilateral has vertices at $(0,1)$, $(3,4)$, $(4,3)$ and $(3,0)$. Its perimeter can be expressed in the form $a\sqrt2+b\sqr

seraphim [82]

Answer:

a + b = 12

Step-by-step explanation:

Given

Quadrilateral;

Vertices of (0,1), (3,4) (4,3) and (3,0)

$Perimeter = a\sqrt{2} + b\sqrt{10}$

Required

$a + b$

Let the vertices be represented with A,B,C,D such as

A = (0,1); B = (3,4); C = (4,3) and D = (3,0)

To calculate the actual perimeter, we need to first calculate the distance between the points;

Such that:

AB represents distance between point A and B

BC represents distance between point B and C

CD represents distance between point C and D

DA represents distance between point D and A

Calculating AB

Here, we consider A = (0,1); B = (3,4);

Distance is calculated as;

$Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

$(x_1,y_1) = A(0,1)$

$(x_2,y_2) = B(3,4)$

Substitute these values in the formula above

$Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

$AB = \sqrt{(0 - 3)^2 + (1 - 4)^2}$

$AB = \sqrt{( - 3)^2 + (-3)^2}$

$AB = \sqrt{9+ 9}$

$AB = \sqrt{18}$

$AB = \sqrt{9*2}$

$AB = \sqrt{9}*\sqrt{2}$

$AB = 3\sqrt{2}$

Calculating BC

Here, we consider B = (3,4); C = (4,3)

Here,

$(x_1,y_1) = B (3,4)$

$(x_2,y_2) = C(4,3)$

Substitute these values in the formula above

$Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

$BC = \sqrt{(3 - 4)^2 + (4 - 3)^2}$

$BC = \sqrt{(-1)^2 + (1)^2}$

$BC = \sqrt{1 + 1}$

$BC = \sqrt{2}$

Calculating CD

Here, we consider C = (4,3); D = (3,0)

Here,

$(x_1,y_1) = C(4,3)$

$(x_2,y_2) = D (3,0)$

Substitute these values in the formula above

$Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

$CD = \sqrt{(4 - 3)^2 + (3 - 0)^2}$

$CD = \sqrt{(1)^2 + (3)^2}$

$CD = \sqrt{1 + 9}$

$CD = \sqrt{10}$

Lastly;

Calculating DA

Here, we consider C = (4,3); D = (3,0)

Here,

$(x_1,y_1) = D (3,0)$

$(x_2,y_2) = A (0,1)$

Substitute these values in the formula above

$Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

$DA = \sqrt{(3 - 0)^2 + (0 - 1)^2}$

$DA = \sqrt{(3)^2 + (- 1)^2}$

$DA = \sqrt{9 + 1}$

$DA = \sqrt{10}$

The addition of the values of distances AB, BC, CD and DA gives the perimeter of the quadrilateral

$Perimeter = 3\sqrt{2} + \sqrt{2} + \sqrt{10} + \sqrt{10}$

$Perimeter = 4\sqrt{2} + 2\sqrt{10}$

Recall that

$Perimeter = a\sqrt{2} + b\sqrt{10}$

This implies that

$a\sqrt{2} + b\sqrt{10} = 4\sqrt{2} + 2\sqrt{10}$

By comparison

$a\sqrt{2} = 4\sqrt{2}$

Divide both sides by $\sqrt{2}$

$a = 4$

By comparison

$b\sqrt{10} = 2\sqrt{10}$

Divide both sides by $\sqrt{10}$

$b = 2$

Hence,

a + b = 2 + 10

a + b = 12

3 0

3 years ago

If B is the midpoint of AC, and AB=5/2x+12 and AC=12x-4, what is the length of BC?

Setler [38]

Answer:

22

Step-by-step explanation:

We know that AC = 2 * AB so we can write:

12x - 4 = 2(5/2 x + 12)

12x - 4 = 5x + 24

7x = 28

x = 4

Since AB = BC the answer is 5/2 * 4 + 12 = 22.

8 0

3 years ago

Determine whether a relation is a function, as well as its domain and range: State the domain and range for the function f(x)=x^

Anna35 [415]

F(x) = x^2 + 3 is a function.
domain of f(x) = x^2 + 3 is all real numbers.
range is all real numbers greater or equal to 3.

6 0

3 years ago

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How to calculate 1/2 × 24cm²​

How to calculate 1/2 × 24cm²