Given that the first spinner has three equal sectors labelled 1, 2 and 3; and the second spinner has equal sectors labelled 3, 4, 5 and 6.
The number of possible outcomes that do not show a 1 on the first spinner is 2 (i.e. the first spinner shows 2 or 3).
The number of possible outcomes that the second spinner show the number 4 is 1 (i.e. the second spinner shows 4)
In probability, the word 'and' goes with multiplication.
Therefore, <span>the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner</span> is given by 2 x 1 = 2 possible outcomes.
i.e. the first spinner shows the number 2 and the second spinner shows the number 4 or the first spinner shows the number 3 and the second spinner shows the number 4.
Answer:
I think that school is somewhat fun, now it is just straight up boring, and yeah sometimes I feel like there are not smart people, and there are weird people, so annoying, I wish they aren't there a lot, but hey, if you can, listen to music, and maybe make some time to do what you like so you can forget about school for a little and relieve your stressssss
Answer:
D 11.61
Step-by-step explanation:
Arc length is
r=5 and angle measure is 133
D. 640
5x^3y^2
5(2)^3(4)^2
5(8) • 16
40 • 16
640
These are linear equations that can be solved simultaneously;
5m+3n=41
3m-6n=9 (multiplying the first equation by 3 and the second by 5)
15m+9n=123
15m-30n= 45 (subtracting the two equations)
39n = 78
n = 2,
and for m, 3m = 9+6(2)
= 21
m = 7
Therefore, n=2 and m=7
