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Alex Ar [27]
3 years ago
14

PLEASE HELP I HAVE NO IDEA WHAT TO DO

Chemistry
1 answer:
larisa86 [58]3 years ago
8 0

The percent yield : 88.4%

<h3>Further explanation</h3>

Reaction

Salicylic acid (C₇H₆O₃) reacts with acetic anhydride (C₄H₆O₃) to form acetylsalicylic acid (C₉H₈O₄)

2C₇H₆O₃(aq)+C₄H₆O₃(aq)⇒2C₉H₈O₄(aq) + H₂O(l)

MW C₇H₆O₃ : 138.12 g/mol

mol C₇H₆O₃

\tt \dfrac{200}{138.12}=1.45

MW C₉H₈O₄ : 180.16 g/mol

mol C₇H₆O₃ = mol C₉H₈O₄ (mol ratio from equation 2:2), so mass of C₉H₈O₄

\tt 1.45\times 180.16=261.232~g

percent yield :

\tt =\dfrac{actual}{theoretical}=\dfrac{231}{261.232}=0.884=88.4\%

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3 years ago
A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the
Damm [24]

Answer:

See solution.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:

\%  M=\frac{m_M}{m_M+2*m_O}*100 \%\\\\59.93\%  =\frac{m_M}{m_M+32.00}*100 \%

Thus, we solve for the molar mass of the metal to obtain:

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For the subsequent problems, we proceed as follows:

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4.00gO_2*\frac{1molO_2}{32.00gO_2}=0.125molO_2

b.

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Regards!

7 0
3 years ago
2. A 2.5 mol SAMPLE OF OXYGEN GAS (O2) INCREASES TO 3.2 mol
lana [24]

696.32 mmHg is the final pressure of the gas.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation, pV = nRT, is an equation used to calculate either the pressure, volume, temperature or number of moles of a gas.

Given data:

P_1 = 720 mmHg              

P_2 = ?

n_1 = 2.5 mol                

n_2 = 3.2 mol

V_1 = 34 L            

V_2 = 45 L

Formula

Combined gas law

\frac{P_1 V_1}{n_1}  = \frac{P_2 V_2}{n_2}

P_2 = 696.32 mmHg

Hence, 696.32 mmHg is the final pressure of the gas.

Learn more about an ideal gas equation here:

brainly.com/question/19251972

#SPJ1

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2 years ago
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