Answer:
THE SPECIFIC HEAT OF THE ALLOY IS 0.9765 J/g K
Explanation:
Mass of alloy = 33 g
Initial temperature of alloy = 93°C
Mass of water = 50 g
Initail temp. of water = 22 °C
Heat capacity of calorimeter = 9.20 J/K
Final temp. = 31.10 °C
specific heat of alloy = unknown
specific heat capacity of water = 4.2 J/g K
Heat = mass * specific heat * change in temperature = m c ΔT
Heat = heat capcity * chage in temperature = Δ H * ΔT
In calorimetry;
Heat lost by the alloy = Heat gained by water + Heat of the calorimeter
mc ΔT = mcΔT + Heat capacity * ΔT
33 * C * ( 93 - 31.10) = 50 * 4.2 * ( 31.10 -22) + 9.20 * ( 31.10 -22)
33 * C * 61.9 = 50 * 4.2 * 9.1 + 9.20 * 9.1
2042.7 C = 1911 + 83,72
C = 1911 + 83.72 / 2042.7
C = 1994.72 /2042.7
C =0.9765 J/g K
The specific heat of the alloy is 0.9765 J/ g K
Is this a question or a statement?
Answer: metal and carbonate
Explanation:
According to Arrhenius concept, a base is defined as a substance which donates hydroxide ions 
when dissolved in water and an acid is defined as a substance which donates hydrogen ions 
in water.
An acid is represented as :
1. When metal is treated with an acid such as 
, if the metal is more reactive than hydrogen displaces hydrogen from its salt solution and thus produce zinc chloride and hydrogen gas.
2. When carbonates are treated with acid, double displacement takes place ad carbon dioxide is released as a gas.
Answer: N3 H12 P O3
Explanation:
From the question :
N = 31.57% H = 9.10% P = 23.27%
O= 36.06%
Divide each of the element by their respective relative atomic masses.
N = 31.57 / 14 = 2.26
H = 9.10/ 1 = 9.10
P = 23.27 / 31= 0.750
O =36.06 / 16 = 2.25
Divide each answer by the lowest of them all, we then have:
N = 2.26/ 0.750 = Approx = 3
H = 9.10 / 0.750 = Approx = 12
P = 0.750/ 0.750= 1
O = 2.25 / 0.750 = Approx = 3
The empiral formula is
N3 H12 P O3
