For solving steps use photomath
The 50th term in the sequence is 199
Arithmetic sequence
The nth term of an arithmetic sequence is expressed as:
Tn = a+ (n - 1)d
where:
- a is the first term
- n is the number of terms
- d is the common difference
The sequence formed by the amount of Whatchamacallits produced as;
3, 7, 11, 15...
a = 3
d = 11-7 = 7-3 = 4
Substitute
Tn = 3 + (n-1) * 4
Tn = 3 + 4n -4
Tn = 4n - 1
Hence the explicit formula that models the production for the nth term of the sequence is Tn = 4n - 1
If n = 50
T50 = 4(50) - 1
T50 = 199
Hence the 50th term in the sequence is 199
Learn more on sequence here; brainly.com/question/6561461
Answer:
25020, 25920, 25425
Step-by-step explanation:
To find if our number is divisible by 5 the number must end with 0 or 5, divisibility by 9 is if sum of all numbers in number is divisible by 9,
We know B must end with 0 or 5
1. Case 25A20 sum of that number is 9 so if we pick 0 as A we have first number because 9/9=1
We can put A as 9 because 18/9=2
2. Case B = 0, sum is 14 so we need pick A as 4 to get 18.
Answer:
7/22 or 0.31818...
Step-by-step explanation:
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