PLEASE HELP ME IM DESPERATE! Given the number of sides of a polygon, what is the maximum number of right angles it can have? Spe
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Answer:
d- m<1 = 58
Step-by-step explanation:
To find this answer we have to do multiple steps.
So we know that vertical angles are congruent by the definition of vertical angles, <u><em>look at the picture</em></u>
So, we also know that a triangle =180 degrees
therefore we can add 32 and 90 to find the 3rd angle measure
32+90=122, then 180(because that's the total of the triangle)-122=58
So, m<1=58 degrees
is the number <em>L</em> such that
Consider the first 7 multiples of 5:
5, 10, 15, 20, 25, 30, 35
Taken mod 7, these are equivalent to
5, 3, 1, 6, 4, 2, 0
This tells us that 3 is the inverse of 5 mod 7, so <em>L</em> = 3.
Similarly, compute the inverses modulo 7 of 2 and 3:
since 2*4 = 8, whose residue is 1 mod 7;
which we got for free by finding the inverse of 5 earlier. So
and so <em>R</em> = 2.
Then <em>L</em> - <em>R</em> = 1.