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VladimirAG [237]
2 years ago
5

CAN YOU PLZ ANSWER THE QUESTION IT IS THE PICTURE!!!

Mathematics
2 answers:
kupik [55]2 years ago
7 0

Answer:

17 pizzas an hour

Step-by-step explanation:

just keep adding just keep adding just keep adding adding adding

Daniel [21]2 years ago
5 0

Answer:

hours 12345

# pizzas 18 31 49 67 85

Step-by-step explanation:

please pick brainlist

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chubhunter [2.5K]
Yeah not just one letter but two letters perpendicular to another two letters. Each 2 letters like AB is a straight line which is crossed by another 2 letters making it perpendicular.
4 0
3 years ago
The triangles below are similar. Triangle Y X Z. Side Y X is 6 centimeters, X Z is 7 centimeters, and Z Y is 3 centimeters. Tria
kotykmax [81]

Answer:

I would go with c.

Step-by-step explanation:

Hope this helped!

7 0
2 years ago
Read 2 more answers
FIND THE AREA...!!!!!
k0ka [10]
I think C I’m not sure but if you want me to explain I multiplied 12 x 10 and 20 x 6 and they both equal 120. So then I added 120 + 120 and got 240. Then u just added 8 because 8 was never use. Which will now look like 240 + 8 and that equal 248. :)
3 0
3 years ago
Carmen has an average of 8 on two 10-point math quizzes. If she scored 10 on the third quiz, what is true of Carmen's average sc
lana [24]

Answer:

9

Step-by-step explanation:

5 0
3 years ago
Three consecutive vertices of a parallelogram are (– 2, 1); (1, 0) and (4, 3). Find the coordinate of the fourth vertex and find
antiseptic1488 [7]

Answer:

D(1,4) - the fourth vertex, the area is equal to 12

Step-by-step explanation:

A(2,-1), B(1,0),C(4,3), They are consecutive, we need to find the point D, find the midpoint of AC (O)

xo= (xA+xc)/2    x0= (-2+4)/2=1

y0=(yA+yC)/2    y0= (1+3)/2=2

0(1,2)

O is the midpoint of BD, so let's find the vertex D

X0= (xB+xD)/2     1= (1+xD)/2   xD=1

y0= (yB+yD)/2      2= (0+yD)/2    yD=4

D(1,4)

the vector DA is (-2-1, 1-4)= (-3,-3)

the vector DC is (4-1, 3-4)= (3,-1)

The modul of DC is sqrt ((-3)^2+(-3)^2)= 3*sqrt2(the length of the side Dc)

The modul of DA is sqrt (3^2+(-1)^2)= sqrt10(the length of the side DA)

cosD= (-3*3+(-3)(-1))/3*sqrt2*sqrt10=-6/3*2*sqrt5=-1/sqrt5

sinD= sqrt (1- 1/5)=2/ sqrt5

S=3sqrt2*sqrt10*2/sqrt5= 12

6 0
2 years ago
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