Answer:
The area of triangle for the given coordinates is 1.5
Step-by-step explanation:
Given coordinates of triangles as
A = (0,0)
B = (3,4)
C = (3,2)
So, The measure of length AB = a = 
Or, a = 
Or, a = 
Or, a = 
∴ a = 5 unit
Similarly
The measure of length BC = b = 
Or, b = 
Or, a = 
Or, b = 
∴ b = 2 unit
And
So, The measure of length CA = c = 
Or, c = 
Or, c = 
Or, c = 
∴ c =
unit
Now, area of Triangle written as , from Heron's formula
A = 
and s = 
I.e s = 
Or. s = 
So, A = 
Or, A = 
Or, A =
× 
∴ Area of triangle = 1.5
Hence The area of triangle for the given coordinates is 1.5
Answer
A+(n-1)d=nth term
a----first term(260)
d----common difference(-52)
Hope it helps!!
Given problems;
1. Factor; x²+5x-24
To factor this equation, we must understand that this is a quadratic equation.
A quadratic equation usually has two roots.
x²+5x-24 = 0
- Then find two numbers whose product is -24 and their sum is +5
the numbers are +8 and -3
then replace 5x with the number;
x² + 8x - 3x - 24 = 0
Now factorize;
x(x +8) - 3(x + 8) = 0
(x-3)(x+8) = 0
Factoring gives (x-3)(x+8)
2. Factor 2n² - 5n -3;
Equate to zero;
2n² - 5n -3 = 0
Find the number whose sum is -5 and the product gives -6( 2 x -3);
the number is -6 and +1;
2n² - 6n + n -3 = 0
2n(n-3) + 1(n-3) = 0
(2n + 1)(n-3) = 0
The factor of the equation is (2n + 1)(n-3).