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ruslelena [56]
2 years ago
14

Write the following compound statement in symbolic form.

Mathematics
1 answer:
skelet666 [1.2K]2 years ago
7 0

Answer:

A conjunction is a compound statement formed by combining two statements using the word and . In symbolic logic, the conjunction of p and q is written p∧q . A conjunction is true only if both the statements in it are true.

Step-by-step explanation:

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On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
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Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

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3 years ago
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Answer: 30:65

Step-by-step explanation:

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2 years ago
The first four terms of a sequence are shown.
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4 0
3 years ago
1. Factor x²+5x-24 <br> 2. Factor 2n²-5n-3
Fynjy0 [20]

Given problems;

 1. Factor;  x²+5x-24

To factor this equation, we must understand that this is a quadratic equation.

A quadratic equation usually has two roots.

  • Equate to zero;

            x²+5x-24 = 0

  • Then find two numbers whose product is -24 and their sum is +5

  the numbers are  +8 and -3

 then replace 5x with the number;

        x² + 8x - 3x - 24  = 0

Now factorize;

     x(x +8) - 3(x + 8) = 0

        (x-3)(x+8)  = 0

Factoring gives (x-3)(x+8)

2. Factor 2n² - 5n -3;

Equate to zero;

   2n² - 5n -3 = 0

Find the number whose sum is -5 and the product gives -6( 2 x -3);

      the number is -6 and +1;

   2n² - 6n + n -3 = 0

   2n(n-3) + 1(n-3) = 0

     (2n + 1)(n-3) = 0

The factor of the equation is (2n + 1)(n-3).

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3 years ago
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Points can define an angle
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