Answer:
The solution of the first image is: b = √48
The solution of the second image is: c = √125
Step-by-step explanation:
Here we have two triangle rectangles, first, we need to remember the Pythagorean theorem.
For a triangle rectangle with cathetus A and B, and a hypotenuse H, we have the relationship:
A^2 + B^2 = H^2
Where H is the side that is opposite to the right angle (the angle of 90°)
In the first image, we can see that the hypotenuse is equal to 8, and one cathetus is equal to 4.
We want to find the value of b, that is the other cathetus.
Then we have:
4^2 + b^2 = 8^2
b^2 = 8^2 - 4^2
b^2 = 48
b = √48
Second image:
in this case, c is the hypotenuse, a and b are the cathetus.
We know that:
a = 5, b = 10
Then we have the equation:
a^2 + b^2 = c^2
Now we can replace the above values:
5^2 + 10^2 = c^2
25 + 100 = c^2
125 = c^2
√125 = c
Answer:
64x^2-9y^2
Step-by-step explanation:
hope this helps, have a good day!
I need to know which question it is though
Two common tangents occur when two circles intersect each other at two points.
<h3>How to illustrate the information?</h3>
It should be noted that two common tangents are also referred to as transverse common tangents.
In this case, two common tangents occur when two circles intersect each other at two points.
The diagram is attached.
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brainly.com/question/4470346
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