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vampirchik [111]
3 years ago
6

Simplify problem if possible

Mathematics
1 answer:
sergeinik [125]3 years ago
3 0
\left(\frac{(x^4y^{-2})^4}{(2x^2)^2\cdot2x^0y^3}\right)^2=\\
\left(\frac{x^{16}y^{-8}}{4x^4\cdot2y^3}\right)^2=\\
\left(\frac{x^{16}y^{-8}}{8x^4y^3}\right)^2=\\
\left(\frac{x^{12}y^{-11}}{8}\right)^2=\\
\frac{x^{24}y^{-22}}{64}
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1. Closed
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