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Julli [10]
3 years ago
14

Cindy spends $85 a month on her cell phone plan. She has saved $1,105 to pay her phone bill. How many months will Cindy be able

to pay for her phone plan?
Mathematics
2 answers:
True [87]3 years ago
7 0

Answer: SHE GOT 13 MONTHS YES SHE DO, 13 MONTHS LEFT IS ANSWER

Step-by-step explanation:

bazaltina [42]3 years ago
7 0

Answer:

mark brainliest plz mark brainliest plz

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Using a calculator can help. You get 0.625, or 5/8.

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Step-by-step explanation:

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4 years ago
Read 2 more answers
How any is?<br> 8m + 27 = 2m - 3 <br> with procedure and testing
givi [52]
8m+27= 2m-3
take 2m and subtract it from 8m, this gives you 6m. now your equation is 6m+27=-3.
subtract 27 from -3, this will make it 6m=-30.
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3 0
3 years ago
Read 2 more answers
The management of a department store is interested in estimating the difference between the mean credit purchases of customers u
Mkey [24]

Answer:

Step-by-step explanation:

1) Point estimate is the difference between the sample means. Therefore,

A point estimate for the difference between the mean purchases of the users of the two credit cards is = 140 - 125 = $15

2) Margin of error = z√(σ²/n1 + σ2²/n2)

Where

z is the z score from the 95% confidence level. From the normal distribution table, z = 1.96

s1 and s2 are standard deviation for both customers respectively.

Standard deviation = √variance

σ1 = √100 = 10

σ2 = √641 = 25.32

Margin of error = 1.96√(10²/64 + 25.32²/49 = 7.5

At 95% confidence, the margin of error is 7.5

3) The confidence interval for the difference of two population means is expressed as point estimate ± margin of error

Confidence interval = 15 ± 7.5

The upper boundary for the confidence interval is

15 - 7.5 = 7.5

The lower boundary for the confidence interval is

15 + 7.5 = 22.5

A 95% confidence interval estimate for the difference between the average purchases of the customers using the two different credit cards is $7.5 to $22.5

4) Since the population standard deviations are known, we would use the formula to determine the test statistic(z score)

z = (x1 - x2)/(√σ1²/n2 + σ2²/n2)

z = (140 - 125)/√10²/64 + 25.32²/49

z = 1.02

The test statistic for an alpha of .05 is 1.02

4 0
3 years ago
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