Question

In the figure below, Triangle FGH and Triangle JKHare right triangles.

Answer 1

Answer:

5

Step-by-step explanation:

∆FGH is similar to ∆JKH. Therefore, their corresponding lengths are proportional to one another. Thus:

$\frac{GH}{KH} = \frac{FH}{JH}$

GH = x + 15

KH = x

FH = 12 + 4 = 16

JH = 4

Plug in the values

$\frac{x + 15}{x} = \frac{16}{4}$

Cross multiply

$(x + 15) \times 4 = 16 \times x$

$4x + 60 = 16x$

Subtract 4x from each side

$60 = 16x - 4x$

$60 = 12x$

Divide both sides by 12

x = 5

KH = x = 5