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rosijanka [135]
3 years ago
12

Is the power produced directly proportional to the wind speed, give reasons for your answer?

Mathematics
1 answer:
yuradex [85]3 years ago
4 0

Answer:

Is the power produced directly proportional to the wind speed.

No.

A proportional function can be described as y = a * x

So (0, 0) is on the graph, not (3, 0).

0 / 3 = 0

3800/6 = 633.33

7600/9 = 844.44

13600/12 = 1133.33

The quotient y/x should be always the same.

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Question five for geometry quiz
Helga [31]

The two tangents are parallel to each other because the two lines perpendicular to the same line are parallel to each other.

Lk + JK = JL




The answer is Parallel to each other
3 0
3 years ago
I will give brainliest for correct answer!
zavuch27 [327]

Answer:

you forgot the question

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If you flip a fair coin 7 times, what is the probability that you will get exactly 4 tails?
kherson [118]

Answer:

u should have another number in here

Step-by-step explanation:

7 0
2 years ago
3. Let A, B, C be sets and let ????: ???? → ???? and ????: ???? → ????be two functions. Prove or find a counterexample to each o
Fiesta28 [93]

Answer / Explanation

The question is incomplete. It can be found in search engines. However, kindly find the complete question below.

Question

(1) Give an example of functions f : A −→ B and g : B −→ C such that g ◦ f is injective but g is not  injective.

(2) Suppose that f : A −→ B and g : B −→ C are functions and that g ◦ f is surjective. Is it true  that f must be surjective? Is it true that g must be surjective? Justify your answers with either a  counterexample or a proof

Answer

(1) There are lots of correct answers. You can set A = {1}, B = {2, 3} and C = {4}. Then define f : A −→ B by f(1) = 2 and g : B −→ C by g(2) = 4 and g(3) = 4. Then g is not  injective (since both 2, 3 7→ 4) but g ◦ f is injective.  Here’s another correct answer using more familiar functions.

Let f : R≥0 −→ R be given by f(x) = √

x. Let g : R −→ R be given by g(x) = x , 2  . Then g is not  injective (since g(1) = g(−1)) but g ◦ f : R≥0 −→ R is injective since it sends x 7→ x.

NOTE: Lots of groups did some variant of the second example. I took off points if they didn’t  specify the domain and codomain though. Note that the codomain of f must equal the domain of

g for g ◦ f to make sense.

(2) Answer

Solution: There are two questions in this problem.

Must f be surjective? The answer is no. Indeed, let A = {1}, B = {2, 3} and C = {4}.  Then define f : A −→ B by f(1) = 2 and g : B −→ C by g(2) = 4 and g(3) = 4. We see that  g ◦ f : {1} −→ {4} is surjective (since 1 7→ 4) but f is certainly not surjective.  Must g be surjective? The answer is yes, here’s the proof. Suppose that c ∈ C is arbitrary (we  must find b ∈ B so that g(b) = c, at which point we will be done). Since g ◦ f is surjective, for the  c we have already fixed, there exists some a ∈ A such that c = (g ◦ f)(a) = g(f(a)). Let b := f(a).

Then g(b) = g(f(a)) = c and we have found our desired b.  Remark: It is good to compare the answer to this problem to the answer to the two problems

on the previous page.  The part of this problem most groups had the most issue with was the second. Everyone should  be comfortable with carefully proving a function is surjective by the time we get to the midterm.

3 0
3 years ago
3. 8x + 4y<br>24 and 6x + 6y = 6​
anzhelika [568]

Answer:

x and y

Step-by-step explanation:

Variables are always the numbers that're replaced with a letter. For example, in the equation:

2t+6

t would be the variable.

Hope this helps!! <3 :)

5 0
2 years ago
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