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SIZIF [17.4K]
3 years ago
10

I need help ASAP !!!!!!

Mathematics
1 answer:
pashok25 [27]3 years ago
5 0

Answer:

x=11

Step-by-step explanation:

First, we notoce that the angles has to be 90 degrees because the other angle is also 90 and these angles have to add up to 180. So, that means 7x+13=90

    -13  -13

7x=77

x=11

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Separate 60 into two parts so that 3 times the smaller added to 6 more than 6 times the smaller = 60.
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Find the center and the radius of the circle with the equation x^2 -2x+y^2 +4y +1
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3 years ago
13. What is the result of adding 5.4a + 7.1 and -1.28 - 6.3?
den301095 [7]

Answer:

C. 4.2a + 0.8

Step-by-step explanation:

Given:

The two binomials given for addition are:

5.4a+7.1 and -1.2a-6.3

Now, adding both the binomials, we get:

5.4a+7.1+(-1.2a-6.3)

Distributing the positive sign inside the second binomial, we get:

5.4a+7.1-1.2a-6.3

Now, combining like terms using the commutative property of addition, we get:

(5.4a-1.2a)+(7.1-6.3)

Simplifying the above expression, we get:

(5.4-1.2)a+0.8\\4.2a+0.8

Therefore, the resulting addition of the given binomials is 4.2a+0.8

Hence, option C is the correct answer.

8 0
3 years ago
Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
  •  4
  • 5
  • 0
  • 1.5sin(3t)
  • 1
  •  2.5

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

7 0
3 years ago
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