Answer:
-14
Step-by-step explanation:
Replace the 2 for each k.
then solve it using PEDMAS: exponents first
= -14
Avocado out!!!!!!!!
Group and factor
undistribute then undistribute again
remember
ab+ac=a(b+c)
this is important
6d^4+4d^3-6d^2-4d
undistribute 2d
2d(3d^3+2d^2-3d-2)
group insides
2d[(3d^3+2d^2)+(-3d-2)]
undistribute
2d[(d^2)(3d+2)+(-1)(3d+2)]
undistribute the (3d+2) part
(2d)(d^2-1)(3d+2)
factor that difference of 2 perfect squares
(2d)(d-1)(d+1)(3d+2)
77.
group
(45z^3+20z^2)+(9z+4)
factor
(5z^2)(9z+4)+(1)(9z+4)
undistribuet (9z+4)
(5z^2+1)(9z+4)
You can first take out an x^2 from each number , 3x^6 - 39x^4 + 108x^2 = x^2 ( 3x^4 - 39x^2 + 108) Then just factor and solve for the zero's of the equation
Answer:
3/2
Step-by-step explanation:
Okay, I can represent this equation as rise over run
the coordinates 4,6 are subcoordinates 1
y: 6 - 3 = 3
x: 4 - 2 = 2
Since it is RISE over run then Y is the numerator and X is the denominator.
So the slope is 3/2.
The guy on top is correct
