Well for 3. you use the Pythagorean theorem to say that 28^2 - 18^2= x^2 so 21.4 and for 4. the Pythagorean theorem says a^2 + b^2 = c^2 with c being the hypotenuse of any right triangle so the sums of the two smaller squares make the sum of the larger square making the answer b
Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
Step-by-step explanation:
The center of a circle with 2 end points of a di diameter is the midpoint of the two endpoints.
The formula needed to find the minpoints is
(x,y) = (x2 + x1)/2, (y2 + y1)/2
x2 = 3
x1 = 3
y2 = 0
y1 = -7
midpoint = (3 + 3)/2, (0 - 7)/2
midp[oint = 3,-3.5
The midpoint is the center of the circle. Observe that the signs get changed when entering the values for (x,y)
So far what you have is (x - 3)^2 + (y + 3.5)^2 = r^2
To determine r^2 you need only take the distance from the center to oneof the endpoints.
r^2 = (3 - 3)^2 + (3.5 - 0)^2
r^2 = 3.5^2
r^2 = 12.25
Answer: (x - 3)^2 + (y + 3.5)^2 = 12.25
Answer:
Written out the equation would look like f(x) = 55(1.06)^x
The graph would look something like the attached picture. (It intercepts with the y-axis at 55).
