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3 years ago

If sin⁡ θ>0 and tan⁡ θ<0, in which quadrant does the terminal side of θ lie?

Mathematics

1 answer:

AlladinOne [14]3 years ago

8 0

Answer:

Quadrant IV

Step-by-step explanation:

For an angle in the fourth quadrant the point P has positive x coordinate and negative y coordinate. Therefore: In Quadrant IV, cos(θ) > 0, sin(θ) < 0 and tan(θ) < 0 (Cosine positive). The quadrants in which cosine, sine and tangent are positive are often remembered using a favorite mnemonic.

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6(-2-3x)+8=68 Find x

yawa3891 [41]

$6(-2-3x)+8=68 \\ 6(-2-3x)=60 \\ -12-18x=60 \\ -18x=72 \\ 18x=-72 \\ x= \frac{-72}{18} \\ \\ \boxed{x=-4}$

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3 years ago

Read 2 more answers

The formula is: <img src="https://tex.z-dn.net/?f=v%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%7Br%7D%5E%7B3%7D%20" id="TexFor

uranmaximum [27]

Answer:

Volume of hemisphere=

$\frac{2}{3} \pi {r}^{3}$

Volume of sphere=

$\frac{4}{3} \pi {r}^{3}$

Step-by-step explanation:

$\frac{2}{3} \times \frac{22}{7} \times {8}^{3}$

Using calculator=

1072.761905

Round to the nearest tenth=

1072.8

5 0

3 years ago

Find the missing length. The triangles are similar.

Marina CMI [18]

Answer:

RK= 13 SK= 12

Step-by-step explanation

First, we find the missing length of RK using the given information: 65-52=13

Then we divide 65 by 13 to get a scale factor: 65/13=5

(To check, we multipuly: 13*5=65)

We then apply the scale factor to MK to find SK: 60/5=12

(To check we multipuly: 5*12=60)

We now have our answers: RK:13, SK:12

4 0

3 years ago

After a snowstorm in the town of Golden Glen, the morning temperature was – 10°F. But by the afternoon, the temperature had rise

spayn [35]

Answer:

7°F

Step-by-step explanation:

We have the following information from the question;

Morning temperature = -10°F

Increase in temperate = 17°F

Afternoon temperature = the unknown

Since;

Increase in temperature = Afternoon temperature - morning temperature

Then;

Afternoon temperature = increase in temperature + morning temperature

Afternoon temperature = 17°F + (-10°F)

Afternoon temperature= 7°F

5 0

3 years ago

Given the function f(x) = 4(2)x, section a is from x = 1 to x = 2 and section b is from x = 3 to x = 4. part

Aliun [14]

A. Average rate of change for x=1 to 2: 4(2²)-4(2)=16-8=8; from x=3 to 4: 4(2⁴)-4(2³)=64-32=32.
b. Section b is 32/8=4 times greater. As the exponent of 2 increases, the gaps between consecutive powers of 2 gets wider and therefore the rate of change is greater.

6 0

3 years ago