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Art [367]
3 years ago
10

In Frank's toy bin there are 17 red blocks. There are 2 more yellow blocks than red blocks. There are also 12 more blue blocks t

han red blocks. How many blocks are there in all?
Mathematics
1 answer:
oee [108]3 years ago
5 0

Answer:

65

Step-by-step explanation:

17 red

19 yellow

29 blue

add them together, = 65

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lara31 [8.8K]
For the 1st hour the cost is $50 whatever is the duration (providing it's 1 hour max.

From one hour and onward the cost becomes an additional $25 per quater of an hour.

If y is the cost and x the number of hours, then the equation becomes :

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7 0
3 years ago
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Help please questions are in the picture
vredina [299]

Question number 1:

Answer:

Answer B

Step-by-step explanation:

Add the prices

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3 years ago
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– 6 (2x – 3) – 11
jekas [21]

Answer:

12x + 7 is the answer

Step-by-step explanation:

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3 years ago
Please HELP!!!!
Karolina [17]

Answer:


Step-by-step explanation:

Firstly, note that -2i really is just z = 0 + (-2)i, so we see that Re(z) = 0 and Im(z) = -2.

When we're going from Cartesian to polar coordinates, we need to be aware of a few things! With Cartesian coordinates, we are dealing explicitly with x = blah and y = blah. With polar coordinates, we are looking at the same plane but with angle and magnitude in consideration.

Graphing z = -2i on the Argand diagram will look like a segment of the y axis. So we ask ourselves "What angle does this make with the positive x axis? One answer you could ask yourself is -90°! But at the same time, it's 270°! Why do you think this is the case?

What about the magnitude? How far is "-2i" stretched from the typical "i". And the answer is -2! Well... really it gets stretched by a factor of 2 but in the negative direction!

Putting all of this together gives us:

z = |mag|*(cos(angle) + isin(angle))

= 2*cos(270°) + isin(270°)).

To verify, let's consider what cos(270°) and sin(270°) are.

If you graph cos(x) and look at 270°, you get 0.

If you graph sin(x) and look at 270°, you get -1.

So 2*(cos(270°) + isin(270°)) = 2(0 + -1*i) = -2i as expected.

3 0
3 years ago
If CDE ~ GDF, find ED
qaws [65]

Answer:

10

Step-by-step explanation:

\triangle CDE \sim \triangle GDF.. (given) \\\\\therefore \frac{CD}{GD} =\frac{DE}{DF}.. (csst) \\\\\therefore  \frac{15}{x+3} =\frac{3x+1}{4}\\\\ \therefore   \: 15 \times 4 = (x + 3)(3x + 1) \\  \\ \therefore   \: 60 = 3 {x}^{2}  + x + 9x + 3 \\  \\ \therefore  3 {x}^{2}  + 10x + 3 - 60 = 0 \\ \therefore  3 {x}^{2}  + 10x  - 57 = 0 \\ \therefore  3 {x}^{2}  + 19x - 9x  - 57 = 0 \\ \therefore   \: x(3x + 19) - 3(3x + 19) = 0 \\\therefore   \:  (3x + 19)(x - 3) = 0 \\ \therefore   \: 3x + 19 = 0 \:  \: or \:  \: x - 3 = 0 \\  \therefore   \: x =  -  \frac{19}{3}  \:  \: or \:  \: x = 3 \\  \because \: x \: can \: not \: be \:  - ve \\ \therefore   \: x = 3 \\ ED = 3x + 1 = 3 \times 3 + 1  \\ \huge \red{ \boxed{ ED= 10}}

7 0
3 years ago
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