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igor_vitrenko [27]
3 years ago
10

Solve. 2(2z + 5) = 50​

Mathematics
2 answers:
Nikitich [7]3 years ago
5 0

Answer:

z = 10

Step-by-step explanation:

Distribute 2 to the terms in the parentheses:

2(2z + 5) = 50​

4z + 10 = 50

Subtract 10 from both sides

4z = 40

Divide each side by 4

z = 10

So, the answer is z = 10

aleksklad [387]3 years ago
5 0

Answer:

10

Step-by-step explanation:

1. Factorize left side.

2*2z+2*5=50

4z+10=50

2. Subtract 10 from both sides

4z=50-10

4z=40

3. Divide both sides by 4

z=40/4

z=10

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\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-2})\qquadB(\stackrel{x_2}{0}~,~\stackrel{y_2}{5})\qquad \qquadd = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\AB=\sqrt{[0-(-2)]^2+[5-(-2)]^2}\implies AB=\sqrt{(0+2)^2+(5+2)^2}\\\\\\AB=\sqrt{4+49}\implies \boxed{AB=\sqrt{53}}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\B(\stackrel{x_2}{0}~,~\stackrel{y_2}{5})\qquad C(\stackrel{x_1}{3}~,~\stackrel{y_1}{1})\\\\\\BC=\sqrt{(3-0)^2+(1-5)^2}\implies BC=\sqrt{3^2+(-4)^2}


\bf BC=\sqrt{9+16}\implies \boxed{BC=5}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\C(\stackrel{x_2}{3}~,~\stackrel{y_2}{1})\qquad A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-2})\\\\\\CA=\sqrt{(-2-3)^2+(-2-1)^2}\implies CA=\sqrt{(-5)^2+(-3)^2}\\\\\\CA=\sqrt{25+9}\implies \boxed{CA=\sqrt{34}}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\~\hfill \stackrel{AB+BC+CA}{\approx 18.11}~\hfill

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2 years ago
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