Let us model this problem with a polynomial function.
Let x = day number (1,2,3,4, ...)
Let y = number of creatures colled on day x.
Because we have 5 data points, we shall use a 4th order polynomial of the form
y = a₁x⁴ + a₂x³ + a₃x² + a₄x + a₅
Substitute x=1,2, ..., 5 into y(x) to obtain the matrix equation
| 1 1 1 1 1 | | a₁ | | 42 |
| 2⁴ 2³ 2² 2¹ 2⁰ | | a₂ | | 26 |
| 3⁴ 3³ 3² 3¹ 3⁰ | | a₃ | = | 61 |
| 4⁴ 4³ 4² 4¹ 4⁰ | | a₄ | | 65 |
| 5⁴ 5³ 5² 5¹ 5⁰ | | a₅ | | 56 |
When this matrix equation is solved in the calculator, we obtain
a₁ = 4.1667
a₂ = -55.3333
a₃ = 253.3333
a₄ = -451.1667
a₅ = 291.0000
Test the solution.
y(1) = 42
y(2) = 26
y(3) = 61
y(4) = 65
y(5) = 56
The average for 5 days is (42+26+61+65+56)/5 = 50.
If Kathy collected 53 creatures instead of 56 on day 5, the average becomes
(42+26+61+65+53)/5 = 49.4.
Now predict values for days 5,7,8.
y(6) = 152
y(7) = 571
y(8) = 1631
Answer:
X = 4, 1
Step-by-step explanation:
Multiplying out
X^2 - 2x - 3x +6 = 2
X^2 - 5x +4 = 0
Factoring:
X^2 - 4x - X +4
X(x-4) - 1(x-4)
(x-1)(x-4)=0
X= 1, 4
Answer:
Square root of 1 is 1
Square root of 2 is 1.41421356237 so 1.41
square root of 3 is 1.73205080757 so 1.73
Step-by-step explanation:
X<-7 so the answer would be greater*
In a quadratic equation with the general formula of:
ax^2 + bx + c = 0
The discriminant is equal to b^2 - 4(a)(c). If the answer is a perfect square, then there are two real numbers. If not, then there are no real number root.
The discriminant for this equation is
(-6)^2 - 4(3)(1) = 24
Since 24 is not a perfect square, there are no real number roots.
