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konstantin123 [22]
2 years ago
7

Question 10 of 10

Mathematics
1 answer:
Pani-rosa [81]2 years ago
6 0

Answer:

A

Step-by-step explanation:

Inverse variation means that y is getting smaller as x gets bigger. The only way for that to happen is with negative numbers or x as a divisor.

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A conjecture and the two-column proof used to prove the conjecture are shown. Given: S is the midpoint of segment R T. Segment R
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given: s is the midpoint of rt

definition of midpoint: rs st

given: st xy

transitive property of congruence: rs xy

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In the diagram, the measurements that are labeled are known, while the other measurements are unknown. Which measurement of acut
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As the sine rule states,

A/sina = B/sinb = C/sinc .

in the diagram, there are two identified sides and if you use the sine rule, you can find the opposed angles easily.

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side b, with angle b.

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A train travels 210.6 miles in 1.3 hours what is the trains average speed?
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Average speed = total distance/ total time
210.6/1.3= 162
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Oranges cost $3.60 per dozen how much does 1 cost?
castortr0y [4]

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There is no set of pound in a gallon because we do not know the substance. Different liquids weigh different amounts.

3.5 gallons is equal to 448 ounces. To find, multiply the number of gallons (3.5) by the amount of ounces in a gallon (128)

3.5 * 128 = 448

Pound and pints are like gallons and pound. Unless we know the substance we cannot solve.

.75 pints is equal to 12 ounces. To find that, we multiply the number of pints (.75) by the number of ounces in a pint (16)

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3 years ago
If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

it comes

x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}

multiply by 3

3x^2-20x+2*16+5=3x^2-20x+37

4 0
3 years ago
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