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8_murik_8 [283]
2 years ago
12

How do I turn this into a radical?

Mathematics
1 answer:
dimaraw [331]2 years ago
7 0
6sqrt(2) i’m pretty sure
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The vertex angle of an isosceles triangle measures 40°. What is the measure of a base angle?
disa [49]
<span>Triangle is 180 degrees, so you will subtract 50 from 180 which will give you 130.</span>
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2 years ago
The pythagorean theorem equation
nikklg [1K]
A^2+b^2=c^2
Is the Pythagorean theorem
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3 years ago
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What is <br> the equation of the line that passes through the points (-6,6) and (-1,-9)
IgorLugansk [536]

Answer:

The answer to the question provided is y = -3x - 12.

Step-by-step explanation:

❃Incase you forgot what the linear equation formula is ☟

y = mx + b

❃Incase you also forgot, what the slope formula is ☟

m = \frac{y_2 - y_1 }{x_2 - x_1}

➊ First: We are going to be solving for the slope.

m = \frac{  - 9 - 6}{ - 1 - ( - 6)} = \frac{ - 15}{ \: \: \: 5} = - 3

➋Second: We find the y-intercept.

y = mx + b \\ 6 = - 3( - 6) + b \\ 6 = 18 + b \\ \frac{  - 18 =  - 18 \: \: \: \: \:  \:  \:  \:  \:  \:  \:  \: }{ - 12 = b}

➌Third: Plug in.

y =  - 3x - 12

6 0
2 years ago
3/7 of 8th graders play sports. is 3/5 of the 8th graders that play sports are boys, what fraction of the 8th graders are boys
Svetach [21]

Answer:

\dfrac{9}{35} is the fraction of 8th graders who are boys.

Step-by-step explanation:

Let total number of 8th graders = x

Given that, \frac{3}{7} of 8th graders play sports

\Rightarrow 8th graders who play sports = \frac{3}{7} \times x

Also, Given that, \frac{3}{5} of 8th graders that play sports are boys

Number of 8th graders that play sports, and are boys = \frac{3}{5} \times \text{Number of 8th graders who play sports}

\Rightarrow \dfrac{3}{5} \times \dfrac{3}{7} \times x\\\Rightarrow \dfrac{9}{35} \times x

Hence, the answer is:

\dfrac{9}{35} is the fraction of 8th graders who are boys.

6 0
2 years ago
The quadratic function h(t)=-16.1t^2 + 150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15
zzz [600]
In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05 
4 0
3 years ago
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