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8_murik_8 [283]
3 years ago
12

How do I turn this into a radical?

Mathematics
1 answer:
dimaraw [331]3 years ago
7 0
6sqrt(2) i’m pretty sure
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Please help me solve this question
finlep [7]

(24·z^3)^2/(27·12·z) = (2^3·3·z^3)^2/(3^3·2^2·3·z) = (2^6·3^2·z^6)/(3^3·2^2·3·z) = 2^4·3^(-2)·z^5

a = 4 ; b = -2 ; c = 5

8 0
3 years ago
Find the area of the circle. Round your answer to the nearest hundredth.
OlgaM077 [116]

Answer:

4.71 ft^2

Step-by-step explanation:

to calculate area its pie * diameter with the diameter in this question being 1.5 and when it says to the nearest hundredth it means to the second away from the point

5 0
2 years ago
SAMPLE QUESTION 2
Arlecino [84]

Answer:

4 rth answer is correct if it is wrong plz comment

Step-by-step explanation:

=14-3/21

=11/21

=

2-1/6

1/6

4-3/12

1/12

5 0
3 years ago
Suppose babies born in a large hospital have a mean weight of 3215 grams, and a variance of 84,681. if 67 babies are sampled at
ziro4ka [17]
The z-score is given by:
z=(x-μ)/σ
but
x-μ=52
thus
z=52/√84681
z=0.1787
Thus:
P(X≤52)=0.9633
7 0
3 years ago
Read 2 more answers
A pharmacist has an 18% alcohol solution and a 40% alcohol solution. How much of each should he mix together to make 10 liters o
ladessa [460]
X = amount of the 18% solution

y = amount of the 40% solution

we know the 18% solution has only 18% of alcohol, the rest is maybe water or something, now, how many liters is 18%?  well, 18% of anything is just (18/100) * anything, so, 18% of x is just (18/100) *x or 0.18x, and that's how many liters are there.

likewise, how many liters are there in the 40% solution?  well, (40/100) * y, or 0.4y, that many.

we know the mixture has to yield 10 liters at 20% alcohol, how many liters of only alcohol is that?  well, (20/100) * 10, or 2 liters.

\bf \begin{array}{lccclll}
&\stackrel{liters}{amount}&\stackrel{alcohol~\%}{quantity}&\stackrel{liters}{alcohol}\\
&------&------&------\\
\textit{18\% solution}&x&0.18&0.18x\\
\textit{40\% solution}&y&0.40&0.4y\\
------&------&------&------\\
mixture&10&0.20&2
\end{array}

\bf \begin{cases}
x+y=10\implies \boxed{y}=10-x\\
0.18x+0.4y=2\\
----------\\
0.18x+0.4\left( \boxed{10-x} \right)=2
\end{cases}
\\\\\\
0.18x-0.4x+4=2\implies -0.22x=-2
\\\\\\
x=\cfrac{-2}{-0.22}\implies x=\cfrac{100}{11}\implies x=9\frac{1}{11}

how much of the 40% solution?  well y = 10 - x
3 0
3 years ago
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