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Paraphin [41]
3 years ago
9

Not sure what the answer is lol

Mathematics
1 answer:
suter [353]3 years ago
6 0

Answer:

A)

Step-by-step explanation:

Congruent figures are always similar. Similar figures have the same shape, but may have different sizes. A dilation may change the size, but it does not change the shape. If a figure is dilated into another, the two figures are always similar.

If you have a combination of congruence transformations and dilations, you will always end up with similar figures.

Answer: A)

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devlian [24]

Answer:

  • find the angle KCO =57+63+x=180
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7 0
3 years ago
The students at a High School earned money for an international animal rescue foundation. 82 seniors earned an average $26.75 pe
Anon25 [30]

Answer: A. $16.13

Step-by-step explanation:

Total students = 82+74+96+99 =351

Sum of earnings of 82 seniors  = $26.75  x 82= $2193.5

Sum of earnings of 74 juniors  = $12.25 x 74 = $906.5

Sum of earnings of 96 sophomores  = $15.50  x 96 = $1488

Sum of earnings of 99 freshmen  =  $10.85 x 99 = $1074.15

Total earnings =  $2193.5  + $906.5+  $1488 +$1074.15

= $5662.15

(Total earnings) ÷ (Total students )

= $5662.15÷ 351

= $16.13

4 0
3 years ago
X-3y-7=0 , 3x-3y-15=0 solve this using cross multiplication​
rewona [7]

Answer:

x = 4 , y = -1

Step-by-step explanation:

x - 3y = 7 -- (1)

3x - 3y = 15 -- (2)

Rewriting (1), x = 3y + 7 -- (1)'

Substituting (1)' into (2),

3 ( 3y + 7 ) - 3y = 15

9y + 21 - 3y = 15

6y = -6

y = -1 -- (3)

Substituting (3) into (1),

x - 3 ( - 1 ) = 7

x + 3 = 7

x = 4 -- (4)

According to (3) and (4),

x = 4 , y = -1

8 0
3 years ago
Which represents the volume of the cylinder, in cubic units?<br><br> 120π<br> 130π<br> 300π<br> 325π
IrinaVladis [17]
Volume=(pi)(radius^2)(height)
Volume=(pi)(5^2)(12)
V=(pi)(25)(12)
V=(pi)(300)
5 0
3 years ago
Read 2 more answers
RIP OpenStudy ;(
klemol [59]
First note that \frac{2^n+1}{2^{n+1}} =  \frac{2^n}{2^{n+1}} + \frac{1}{2^{n+1}} = \frac{1}{2} + \frac{1}{2^{n+1}}

If you take limit, then you have \lim_{n \to \infty}( \frac{1}{2} + \frac{1}{2^{n+1}})= \lim_{n \to \infty}( \frac{1}{2}) +\lim_{n \to \infty}(\frac{1}{2^{n+1}})=\frac{1}{2} +0= \frac{1}{2}



3 0
3 years ago
Read 2 more answers
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