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ki77a [65]
3 years ago
12

Plz Help... Find x in the given triangle.

Mathematics
1 answer:
never [62]3 years ago
6 0

Answer:

\huge\boxed{x=2\sqrt{286}}

Step-by-step explanation:

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have:

leg=x\\leg=15\\hypotenuse=37

Substitute and solve for x:

x^2+15^2=37^2\\\\x^2+225=1269\qquad|\text{subtract 225 from both sides}\\\\x^2+225-225=1269-225\\\\x^2=1144\to x=\sqrt{1144}\\\\x=\sqrt{4\cdot286}\\\\x=\sqrt4\cdot\sqrt{286}\\\\x=2\sqrt{286}

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If the discriminant of a quadratic equation is equal to -8, which statement describes the roots?
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Keywords

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we know that

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x=\frac{-b(+/-)\sqrt{b^{2}-4ac}}{2a}

where

The <u>discriminant</u> of the <u>quadratic equation</u>  is equal to

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if  (b^{2}-4ac)> 0 ----> the <u>quadratic equation</u> has two <u>real roots</u>

if  (b^{2}-4ac)=0 ----> the <u>quadratic equation</u> has one <u>real root</u>

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in this problem we have that

the <u>discriminant</u> is equal to -8

so

the <u>quadratic equation</u> has two <u>complex roots</u>

therefore

the answer is the option A

There are two complex roots

5 0
3 years ago
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Answer: a = \frac{-2}{b - 4}

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