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3 years ago

Please help i need it NOW! NO LINKS!!!!!! Mark as BRAINLLEST to whoever gets it right

Mathematics

1 answer:

GREYUIT [131]3 years ago

3 0

Answer:

Given b=1.7 and ∠β=39°,

x = 2.70133

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On the first day, a company has 64 orders for shipping crates on backorder. Every day customers order 18 more shipping crates. I

SOVA2 [1]

The correct answer is:

B. 14

Explanation:

Let x be the number of days. On day 1, we begin with 64 orders. We gain 18 orders per day; this is 18x, and gives us

64+18x.

We also make 28 crates per day, which decreases the number of crates we need by 28 per day; this is -28x, and gives us

64+18x-28x

Combining like terms, we get

64-10x

For day 5, we replace x with 5:

64-10(5) = 64-50 = 14

4 0

3 years ago

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e^−2

Mekhanik [1.2K]

Answer:

x=1

y=s

z=1

Step-by-step explanation:

(x, y, z)=(1, 0, 1)

Substitute 0 for y

$y = e^{-2t} *sin 4t\\0 = e^{-2t} *sin 4t\\\\0 = e^{-2t} *(\frac{e^{4t}-e^{-4t}}{2j} )\\0 = e^{-2t} *(e^{4t}-e^{-4t} )\\0 = e^{-2t} *e^{4t}*(1-e^{-8t} )\\\\0 = e^{2t}*(1-e^{-8t} )\\\\\\Either \\0 = e^{2t}\\t = -inf\\or\\0 = (1-e^{-8t} )\\(e^{-8t} ) = 1\\ -8t = ln(1) =0\\t=0\\\\$

Confirming if t=0 satisfy the other equation

x = e^−2t cos 4t = e^−2(0)cos(4*0)

= e^(0)cos(0) = 1

z = e^−2t = e^−2(0) = 0

Therefore t=0 satisfies the other equation

Finding the tangent vector at t=0

$\frac{dx}{dt}=-2te^{-2t} cos4t + e^{-2t}(-4sin4t)=-2(0)e^{-2(0)} cos4(0) + e^{-2(0)}(-4sin4(0))=0\\\\ \frac{dy}{dt} =-2te^{-2t} sin4t + e^{-2t}(4cos4t)=-2(0)e^{-2(0)} sin4(0)+ e^{-2(0)(4cos4(0)) }= 1\\\\\frac{dz}{dt} = -2te^{-2t} = -2(0)e^{-2(0)} = 0$

The vector equation of the tangent line is

(1, 0, 1) +s(0,1,0)= (1, s, 1)

The parametric equations are:

x=1

y=s

z=1

6 0

3 years ago

What is the quotient of 7035/15 pls answer this fast

alexgriva [62]

What is the quotient of 7035/15

469 is equivalent to 7035/15

because 7035/15=469

3 0

3 years ago

A traffic helicopter descends 102 meters to be 331 meters above the ground, as illustrated in the diagram to the right. Write an

lana66690 [7]

Answer:

h -102 = 331
h = 433

Step-by-step explanation:

Using the problem statement as the basis for the equation, we can write ...

h -102 = 331

Using the diagram as the basis for the equation, we could write it as ...

h = 331 +102

The original height of the helicopter was 433 m.

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3 years ago

You start with $.50 at the beginning of the year. This amount doubles every month. How much will you have at the end of the 12th

Doss [256]

Take .50 and multiply it by 2 because it doubled. then multiply that by 6 or 12 to get your answer

4 0

3 years ago

Read 2 more answers