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PtichkaEL [24]
3 years ago
14

What is the greatest common factor of 20, 50, and 30?

Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0

Answer:

10

Step-by-step explanation:

You might be interested in
Micah was asked to add the following rational expressions:
FrozenT [24]

Answer: Absolutely Never. No. He didn't do it correctly. Don't you do it.

I have never seen that error on Brainly before, although while I was teaching, I saw it enough times that I could always bet my math classes that I would see that error 100 times by the end of term. I always promised a case of beer for their grad (which would have given them 1 beer each). I never had to pay. They always made the error 100 times as a class.

Micah CANNOT cancel across a plus sign when going from the numerator to the denominator. You have to be able to take an x^2 out of every term or no term. Micah is totally wrong. Don't, whatever you do, follow his example.

Here is the only condition which will permit you that kind of cancellation.

\dfrac{x^4 + 5x^3 + 10x^2 }{3x^4 + 6x^2} = \dfrac{x^2(x^2 + 5x + 10)}{x^2(3x^2 + 6) }

Now Micah can cancel out the x^2. That is the only condition that will work.

6 0
2 years ago
15400=1200(1.04)^t<br> ???
Alex_Xolod [135]
T=log(15,400÷1,200)÷log(1.04)
T=65 years
8 0
3 years ago
60 POINTS AND BRAINLIEST!!!
weeeeeb [17]

Answer:

Step-by-step explanation:

Putting values of x in equation

Y = 4(-3) - 4

= - 12 - 4 = - 16

Y = 4(-2) - 4

= - 8 - 4 = - 12

Y = 4(-1) - 4

= - 4 - 4 = - 8

Y = 4(0) - 4

= 0 - 4 = - 4

Y = 4(1) - 4

= 4 - 4 = 0

Y = 4(2) - 4

= 8 - 4 = 4

Y = 4(3) - 4

= 12 - 4 = 8

6 0
2 years ago
Read 2 more answers
Consider the quadratic equation x squared = 4x - 5. how many solutions does the equation have?
snow_lady [41]

Answer:

The quadratic equation has two complex solutions

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2}=4x-5  

Equate to cero

x^{2}-4x+5=0  

so

a=1\\b=-4\\c=5

substitute in the formula

x=\frac{4(+/-)\sqrt{-4^{2}-4(1)(5)}} {2(1)}

x=\frac{4(+/-)\sqrt{16-20}} {2}

x=\frac{4(+/-)\sqrt{-4}} {2}

Remember that

i^{2}=-1

so

x=\frac{4(+/-)2i} {2}

x=2(+/-)i

therefore

The quadratic equation has two complex solutions

5 0
3 years ago
What is the perimeter of a trapezoid having side-lengths 10 cm, 7 cm, 6 cm, and 7 cm? a. 15 cm c. 25 cm b. 20 cm d. 30 cm
prisoha [69]

Answer:

30

Step-by-step explanation:

6 0
3 years ago
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