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3 years ago

Find the value of x when 6 - 3x = 5x - 10x + 8. The value of x is

Mathematics

2 answers:

katrin2010 [14]3 years ago

7 0

Answer:

Step-by-step explanation:

Simplify

6 + -3x = 5x + -10x + 8

terms:

6 + -3x = 8 + 5x + -10x

Combining like terms: 5x + -10x = -5x

6 + -3x = 8 + -5x

Solving

6 + -3x = 8 + -5x

Move all terms containing x to the left, all other terms to the right. (Remember)

Add '5x' to each side of the equation.

6 + -3x + 5x = 8 + -5x + 5x

Combine the like terms -3x + 5x = 2x

6 + 2x = 8 + -5x + 5x

Combine the like terms again -5x + 5x = 0

6 + 2x = 8 + 0

6 + 2x = 8

Then '-6' to each side of the equation.

6 + -6 + 2x = 8 + -6

Combine the like terms: 6 + -6 = 0

0 + 2x = 8 + -6

2x = 8 + -6

Combine the like terms: 8 + -6 = 2

2x = 2

Then divide each side by '2'.

x = 1

Simplifying

x = 1

ozzi3 years ago

6 0

Answer:

Step-by-step explanation:

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Answer:

x = 7

Step-by-step explanation:

<u>Required equation</u>

8x + 10 = 12x - 18

<u>Solving for x</u>

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Step-by-step explanation:

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3 years ago

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2 years ago

A storage shed is to be built in the shape of a (closed) box with a square base. It is to have a volume of 150 cubic feet. The c

Alenkinab [10]

Answer:

$C(s) = 6s^2 + \dfrac{1500}{s}\\\text{where s is the side of base.}$

Step-by-step explanation:

We are given the following in the question:

A storage shed is to be built in the shape of a (closed) box with a square base.

Volume = 150 cubic feet

Let s be the edge of square base and h be the height.

Volume of cuboid =

$l\times b\times h$

where l is the length, b is the base and h is the height.

Volume of box =

$s^2h = 150\\\\h = \dfrac{150}{s^2}$

Area of base =

$\text{side}\times \text{side} = s^2$

Cost of concrete for the base = $4

Cost of base($) = $4s^2$

Area of roof =

$\text{side}\times \text{side} = s^2$

Cost of material for the roof = $2

Cost of roof ($) = $2s^2$

Area of 4 walls =

$4\times (sh)\\=4sh$

Cost of material for the side = $2.50

Cost of material of side($) =

$2.50\times 4s(\dfrac{150}{s^2})\\\\=\dfrac{1500}{s}$

Total cost

= Cost of base + Cost of 4 sides + Cost of roof

$C(s) = 4s^2 + \dfrac{1500}{s} + 2s^2\\\\C(s) = 6s^2 + \dfrac{1500}{s}$

is the required cost function.

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3 years ago

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tresset_1 [31]

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Step-by-step explanation:

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Hope this helps, good luck on the test! :)

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3 years ago