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3 years ago

9

Tony is making goody bags for her party each bag has six toys for pieces of candy and 12 stickers

1 answer:

Andrei [34K]3 years ago

5 0

Number of bag = x

Then, number of candies & Strickers would be 6x & 12x respectively..

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Use integration by parts to find the integrals in Exercise.<br> ∫(x+6)ex dx.

skelet666 [1.2K]

Answer:

$xe^x+5e^x$

Step-by-step explanation:

We have given integral $\int (x+6)e^xdx$

$\int (xe^x+6e^x)dx$

$\int (I_1+I_2)dx$ , here $I_1=xe^x$ and $I_2=6e^x$

Now first integrate $I_1$

So $I_1=\int xe^x$

Integrating by part

$I_1=x\int e^x-\int e^x\frac{d}{dx}x$

$I_1=x e^x- e^x$

$I_2=6\int e^x=6e^x$

So $I=I_1+I_2=xe^x-e^x+6e^x=xe^x+5e^x$

5 0

3 years ago

If the perimeter of a triangle is 31 ft and two of the side lengths are 15 ft and 10 ft, what is the length of the third side?

erastovalidia [21]

Answer:

C) 6 ft

Step-by-step explanation:

Perimeter is just adding the side lengths together so...

31-15-10=x

6=x

so your answer is 6ft

3 0

2 years ago

Read 2 more answers

Number four please help. Whatever helps gets a Brainly award

pashok25 [27]

29.99 + 35.00 + 3.25 + 3.25 = 71.49

125.00 - 71.49 = 53.51

53.51 ÷ 22.50 = 2.4 = 2

She can buy 2 pairs of shoes.

Hope this helps!!
~Kiwi

8 0

3 years ago

Hello people ~<br>factorise : 5x²+16x+3

son4ous [18]

5x²+16x+3
5x²+15x+x+3
5x(x+3)+1(x+3)
(5x+1)(x+3)

Done!

5 0

2 years ago

Read 2 more answers

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago