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Nataly_w [17]
3 years ago
9

To the nearest tenth what is the length of the hypotenuse of a right triangle if one side measures 4.5meters and the other side

measures 9 meters.
Mathematics
1 answer:
allsm [11]3 years ago
3 0

Answer:

Step-by-step explanation:

c^2 = a^2 + b^2

4.5^2 + 9^2 = 101.25

c = sqrt 101.25 = 10.06 = 10.1 meters

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Christine took 3 tests and had an average of 76. She has one more test to take and she wants an average of 80. What is the lowes
amm1812

Answer: She has to score a minimum of 92 marks to take her average to 80

Step-by-step explanation:

Let the equation be

Three months total = 76 x 3 = 228

(x + 228) / 4 = 80

x + 228 = 80 x 4

x = 320 - 228

x = 92

6 0
3 years ago
Justify each step in solving the equation 4X equals seven times X -3
torisob [31]
4x = 7(x-3)

1.  Distribute that multiplicand 7:  4x = 7x - 21

2.  Group the x terms together:  Subtract 4x from both sides:  0 = 3x - 21

3.  Solve for x:  Add 21 to both sides:  21 = 3x

4.  Divide both sides by 3 to obtain x = 7 (answer)
5 0
3 years ago
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A circle is the collection of points in a plane that are the same distance from a given point in the plane.
RoseWind [281]

Answer:

True - The above statement is true

A circle is the collection of points in a plane that are the same distance from a given point in the plane.

Step-by-step explanation:

  • <em><u>A circle is the set of points in a plane that are a given distance from a given point in the plane. The given point is the center of the circle, and the given distance is the radius.</u></em>
  • In other words; A circle is the set of points in a plane that are equidistant from a given center point.  Therefore; the locus of points at a fixed distance, d, from the point, P is a circle with the given point P as its center and d as its radius.
6 0
3 years ago
Given that cos θ = –12∕13 and θ is in quadrant III, find csc θ.
Trava [24]

Answer:

A

Step-by-step explanation:

We are given:

\displaystyle \cos(\theta)=-\frac{12}{13},\,\theta\in\text{QIII}

Since cosine is the ratio of the adjacent side over the hypotenuse, this means that the opposite side is (we can ignore negatives for now):

o=\sqrt{13^2-12^2}=\sqrt{25}=5

So, the opposite side is 5, the adjacent side is 12, and the hypotenuse is 13.

And since θ is in QIII, sine/cosecant is negative, cosine/secant is negative, and tangent/cotangent is positive.

Cosecant is given by the hypotenuse over the opposite side. Thus:

\displaystyle \csc(\theta)=\frac{13}{5}

Since θ is in QIII, cosecant must be negative:

\displaystyle \csc(\theta)=-\frac{13}{5}

Our answer is A.

7 0
3 years ago
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I really need help please
Mkey [24]
So.. let's say ∡AGB and ∡BGC are say "a" units wide, and ∡CGD and ∡DGE are "b" units wide

notice the picture below

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7 0
3 years ago
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