Let x be the number of child tickets he bought
Let y be the number of adult tickers he bought
① x+y=7 (child tickets+adult ticket=7 tickets in total)
② 2x+4y=24 (price of child tickets+price of adult tickets=$24 in total)
We may simply the second equation since all of the coefficients are divisible by 2.
① x+y=7
② x+2y=12
We can now use elimination by multiplying the second equation by -1.
② -(x+2y=12)
② -x-2y=-12
① x+y=7
② -x-2y=-12
Now putting the equations together,
-y=-5
y=5
x=2
Therefore he bought 2 child tickets and 5 adult tickets
And a quotient. D.
In a division you have:
Quotient = Dividend / Divisor
The result is called the Quotient, the number at the top of the division is called the dividend and the number below is the divisor.
Answer:
The probability of passing the course given that the course taken was statistics = P(pass|C) = 0.7414
Step-by-step explanation:
This is a combined probability question
PASS FAIL Withdrew TOTAL
(C) .238 .044 .039 .321
(S) .559 .051 .069 .679
(T) .797 .095 .108 1
C represents probability data from Calculus exam and S represents probability data from Statistics exam
Compute the probability of passing the course given that the course taken was statistics = P(pass|C)
Mathematically, this is given by
P(pass|C) = P(pass n C)/P(C)
Probability of passing Calculus, P(pass n C) = 0.238 (from the table)
Probability of offering Calculus, P(C) = 0.321 (from the table)
the probability of passing the course given that the course taken was statistics is P(pass|C)
P(pass|C) = 0.238/0.321 = 0.7414
It depends on the breed... I think its kilograms
Answer:
-3
Step-by-step explanation: