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Vadim26 [7]
3 years ago
8

Sara had 88 dollars to spend on 8 books. After buying them she had 16 dollars. How much did each book cost?

Mathematics
2 answers:
drek231 [11]3 years ago
8 0

Answer

$9

first take $88 and subtract what you have left which is $16,

88-16 = 72

Now take 72 and divide by number of books bought which was 8

72/8 = 9

So each book cost $9

lozanna [386]3 years ago
6 0
88-16=72/8= 9$ /= division ANSWER each book is 9$
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Answer:

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Step-by-step explanation:

We know that, Area of a triangle = 1/2 * b * h

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height = s

Area = 1/2 * b * h

=>84 = 1/2 * 24 * h

=>84 = 12 * h

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=> 7 = h (in cm)

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A hiker climbs a 5-mile trail up a mountain in 2 hours. On the return trip downhill, she walks the same trail and returns to her
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Answer:

3.33 miles per hour

Step-by-step explanation:

The total distance traveled by the hiker is 5 * 2 = 10 miles, and the total time travelled is 2 + 1 = 3 hours.

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distance = speed * time

With distance = 10 and time = 3, we have:

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(1,3)(0,2)(-4,0) are they collinear
mariarad [96]

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3 years ago
erry jogs the same round trip path everyday. He jogs 0.7 miles to the park and then 0.5 miles from the park to the playground. A
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4 0
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Read 2 more answers
The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand
Maurinko [17]

Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 18.6, \sigma = 5.9

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 18.6}{5.4}

Z = 0.44

Z = 0.44 has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768

This probability is 1 subtracted by the pvalue of Z when X = 20.4. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{20.4 - 18.6}{0.6768}

Z = 2.66

Z = 2.66 has a pvalue of 0.9961

1 - 0.9961 = 0.0039

0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

4 0
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