All categories

2 years ago

Which statement represents the biconditional statement of the conditional statements?

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

3 0

The measures of two angles have a sum of 90º if and only if the angles are complements.

if the angles are complementary they have to equal 90 otherwise they are not complementary

You might be interested in

George is 14 years old. His age is 2 years more than twice his brother, Jhon's age. How old is John?

Luda [366]

Answer:

Step-by-step explanation:

14×2=28

28+2=30

i hate riddles

8 0

2 years ago

PLS HURRY ONLY CORRECT ANSWERS 50 POINTS NEED THIS IN ONE HOUR

Dmitry_Shevchenko [17]

Answer:

250=70x+50

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

2 2/3 * 3/4 answer that

Nataly_w [17]

answer = 2

You can just use a calculator unless you need to show your work

5 0

2 years ago

If (9^2)^p = 9^8, what is the value of p? A. 2 B. 3 C. 4 D. 6

Vikentia [17]

The answer is 4 so C is correct

5 0

2 years ago

Read 2 more answers

The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla

forsale [732]

Answer:

Speed at Equator = 463.97 meters per second

Centripetal Acceleration at Equator = $3.37*10^{-2}$ meters per second squared

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration at 30 degrees north of equator = $2.92*10^{-2}$ meters per second squared

Step-by-step explanation:

The formula is:

$v=\frac{2 \pi R}{T}$

Where

v is speed

R is radius

T is time

and another formula for centripetal acceleration:

$a_c=\frac{4 \pi^{2} R}{T^2}$

Now,

at equator, the radius is radius of earth (given), time in seconds is

T = 24 * 60 * 60 = 86,400

THus,

$v_E=\frac{2 \pi (6.38*10^{6}}{86,400}=463.97$

Speed at Equator = 463.97 meters per second

Centripetal Acceleration:

$a_{cE}=\frac{v_E^2}{R_E}=\frac{463.97}{6.38*10^{6}}=3.37*10^{-2}$

Centripetal Acceleration at Equator = $3.37*10^{-2}$ meters per second squared

At 30.0° north of the equator:

$R_N=R_E Cos (30)= (6.38*10^6)Cos(30)=5.53*10^6$

Now,

Speed = $v_{30N}=\frac{2 \pi (5.53*10^6)}{86,400}=401.79$

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration:

$a_{30N}=\frac{v_E^2}{R_E}=\frac{401.79}{5.53*10^6}=2.92*10^{-2}$

Centripetal Acceleration at 30 degrees north of equator = $2.92*10^{-2}$ meters per second squared

4 0

2 years ago