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3 years ago

On the set of axes below. solve the following

Mathematics

1 answer:

Delvig [45]3 years ago

5 0

Answer:

i think x=1 y=3 (1,3)

Step-by-step explanation:

2x+4x-1 = 5

x = 1

y = 4x-1

y = 4(1)-1

y = 4-1

y = 3

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Pls help

alisha [4.7K]

Answer:

i think it would be 11 cups

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3 years ago

1. Let C be between D and E. Use the Segment addition Postulate to solve for v.

AURORKA [14]

By applying the segment addition postulate, the value of v = 7

According to the Segment Addition Postulate, it holds that if point C is between points D and E, therefore:

DC + CE = DE

Given that:

$DC = 2v-15\\\\CE = 3v-8\\\\DE = 27$

Therefore, by substitution, we will have the following equation:

$(2v-15) + (3v-8) = 27$

Open the bracket and solve for the value of v.

$2v-15 + 3v-8 = 27$

Add like terms

$5v - 23 = 27$

Add 23 to both sides

$5v - 23+ 23 = 27 + 23\\\\5v = 50$

Divide both sides by 5

v = 10

Therefore, using the segment addition postulate, the value of v = 10

Learn more about the segment addition postulate here:

brainly.com/question/1721582

7 0

3 years ago

I need help on how to solve this, it says these are not special right triangles

Tom [10]

The answer is ............................ go to school

6 0

3 years ago

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32pts and BRAINLIEST FOR BST ANSWER!!

Nataliya [291]

Answer:

Step-by-step explanation:

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3 years ago

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Y is directly proportional to square root of x If y=56 when x=49 find, y when x=81

STALIN [3.7K]

$\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}$

$\stackrel{\begin{array}{llll} \textit{"y" directly}\\ \textit{proportional to }\sqrt{x} \end{array}}{y = k\sqrt{x}}\qquad \textit{we know that} \begin{cases} y = 56\\ x = 49 \end{cases}\implies 56=k\sqrt{49} \\\\\\ 56=7k\implies \cfrac{56}{7}=k\implies 8=k~\hfill \boxed{y=8\sqrt{x}} \\\\\\ \textit{when x = 81, what is "y"?}\hfill y=8\sqrt{81}\implies y=8(9)\implies y=72$

7 0

2 years ago