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2 years ago

How do find the nth term in a non-linear sequence

Mathematics

1 answer:

erastovalidia [21]2 years ago

6 0

Answer:an =n-1d

a+1d

a-2d

so that 29 is the sequence

Step-by-step explanation:

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What is the volume of a square pyramid that is 8 feet tall with base edges of 3 feet?

Dennis_Churaev [7]

Answer : 8 ft
Explanation :
You can find the volume of a regular square pyramid using the formula volume = base area × height / 3. Hope it helps.

8 0

2 years ago

A 90% confidence interval for the average weight (in pounds) of Americans was found to be (185, 210). The point estimate for thi

Lynna [10]

Answer:

B. 12.5

Step-by-step explanation:

We have the lowe confidence interval = 185

The upper confidence interval = 210

Mean of X = (lower confidence + upper confidence interval)/2

Mean of X = 185 + 210/2

= 197.5

The margin of error = the upper confidence interval - mean of X

= 210-197.5

= 12.5

3 0

3 years ago

What is the answer ?

fomenos

Answer:

19/60 or .317

Step-by-step explanation:

C = 95/300

95/300 = 19/60

19/60 = .317

3 0

2 years ago

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

______________________________________________________

TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

SOME GENERAL TRIGNOMETRIC FORMULAS :-

$\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

$\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

______________________________________________________

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

3 years ago

What is the image of (2,3)(2,3) after a reflection over the line y=-xy=−x?

otez555 [7]

Answer:

After the reflection over the line y = -x, the image of the point is: (-3,-2)

Step-by-step explanation:

When a given point is reflected over a line the point only changes place but the distance between the point and the line remains same.

Let (x,y) be a point on the plane

and

y = -x be a line on the plane

When a point is reflected over a line y = -x , the coordinates of the point are exchanged which means x becomes y and y becomes x and both are negated

So (x,y) will become (-y,-x)

Given point is:

(2,3)

After the reflection over the line y = -x, the image of the point is: (-3,-2)

4 0

3 years ago