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Anit [1.1K]
3 years ago
9

Which triangle similarity postulate can be used to justify that triangle XYZ is similar to triangle ABC?

Mathematics
2 answers:
galina1969 [7]3 years ago
7 0

I think it is A) i am so sorry if i am wrong

Serga [27]3 years ago
3 0

Answer:

a

Step-by-step explanation:

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Suppose a randomly generated list of numbers from 0 to 9 that has a probability success of 80%. which of these groups of numbers
maria [59]
A is the answer because it is the widest variety
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Calculate the Area of each of the following Figures:​
kotegsom [21]

Answer:

2.2.1 Area = 12.6 cm²

2.2.2 Area = 12 cm²

Step-by-step explanation:

<u></u>

<u>2.2.1:</u>

The radius of the big circle is half the length of the square = 2.5 cm

The radius of the small circle is half of 3 cm = 1.5 cm

The area of the shaded portion is = Area of big circle - Area of small circle

π × 2.5²-π × 1.5² = 12.6 cm²

<u>2.2.2</u>

To find length BD (the height of the parallelogram) we need to use the Pythagorean theorem:

BD = √(5²-3²) = 4

Area = base x height = 3x4 = 12 cm²

3 0
1 year ago
The second term from the end of the A.P. 5.8. 11,......47 is
enyata [817]
D = -(8-5) = -3
a = 47
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7 0
3 years ago
Joey exercised 5/6 of an hour on Monday and 3/5 of an hour on Tuesday. How much longer did he exercise on Monday?
irina [24]

Answer:

5/6 -  3/5 =  7/30

Step-by-step explanation:

Calculation steps:

8 0
3 years ago
Read 2 more answers
Do well-rounded people get fewer colds?
asambeis [7]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if people with less social contact get more colds than people who are involved in a variety of social activities.

For this, a sample of 276 healthy men and women was taken.

n₁= 96 had few social outlets

n₂= 105 had six or more activities

These two groups were exposed to the cold virus and the following proportions of individuals that got sick were obtained:

p'₁= 0.62 (62% of the people with few social outlets got sick)

p'₂= 0.35 (35% of the people with six or more activities got sick)

The study variables are X₁: number of people with few social outlets that got sick after being exposed to the cold virus, in a sample of 96, and X₂: number of people with six or more activities that got sick after being exposed to the cold virus, in a sample of 105.

You have to construct a 99% CI for the difference these two populations since there is no specific order given I'll estimate: p₁ - p₂

(p'₁ - p'₂) ± Z_{1-\alpha /2} * \sqrt{\frac{p'_1(1-p'_1)}{n_1} +\frac{p'_2(1-p'_2)}{n_2} }

Z_{1-\alpha /2}= Z_{0.995}= 2.586

(0.62-0.35) ± 2.586 \sqrt{\frac{0.62*0.38}{96} +\frac{0.35*0.65}{105} }

[0.094; 0.045]

With a 99% confidence level, you'd expect that the difference between the proportion of people with few social outlets that got sick and the proportion of people with six or more social activities that got sick after being exposed to the cold virus.

I hope it helps!

8 0
2 years ago
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