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Maru [420]
3 years ago
13

A teacher read part of a book to a class. The graph shows the number of pages read by the teacher over the next several days. Fi

nd interpret the rate of change and initial value
Mathematics
1 answer:
Lostsunrise [7]3 years ago
5 0

Answer:

no graph nice job if you put a graph i can answer

Step-by-step explanation:

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(High points) please solve with explanation
AysviL [449]

Answer:

The area and the perimeter of the picture are:

  • <u>Area = 160 cm^2</u>
  • <u>Perimeter = 67.31 cm</u>

Step-by-step explanation:

To find the area of that figure, you can find the area how if it was a rectangle and next subtract the area of the triangle in the upper part. The area of a rectangle could be found by the next formula:

  • Area of a rectangle = base * height

As you can see in the picture, the base is 16 cm and the height is 12 cm, then we replace in the formula:

  • Area of a rectangle = 16 cm * 12 cm
  • Area of a rectangle = 192 cm^2

Now, we calculate the area of the triangle to subtract to the area we found and obtain the real area, the formula to obtain the area of a triangle is:

  • Area of a triangle = (base * height) / 2

The height of the triangle is 8 cm, and the base is 8 cm too, because you subtract to the base of the rectangle (16 cm) the measurements in the upper part (16 - 4 - 4 = 8), Now, we replace in the formula:

  • Area of a triangle = (8 cm * 8 cm) / 2
  • Area of a triangle = (64 cm^2) / 2
  • Area of a triangle = 32 cm^2

We subtract to the found area:

  • Area of the picture = 192 cm^2 - 32 cm^2
  • <u>Area of the picture = 160 cm^2</u>

To find the perimeter, you must add all the sides of the picture, but, as you can see, there is a side that doesn't have the measurent, this is the hypotenuse of the triangle used before, but how we know the other sides, we can use Pythagorean theorem:

  • a^{2}+b^{2}=c^{2}

Where:

  • a = Opposite leg (8 cm)
  • b = Adjacent leg (8 cm)

So, we replace in the theorem:

  • a^{2}+b^{2}=c^{2}
  • (8 cm)^{2}+(8cm)^{2}=c^{2} (and we clear c)
  • \sqrt{(8 cm)^{2}+(8cm)^{2}} =c
  • \sqrt{64 cm^{2}+64cm^{2}} =c
  • \sqrt{128cm^{2}} =c
  • c = 11.3137085 cm
  • c ≅ 11.31 cm

At last, we add all the sides of the picture begining by the base and going by the left side:

  • Perimeter of the picture = 16 cm + 12 cm + 4 cm + 11.31 cm + 8 cm + 4 cm + 12 cm
  • <u>Perimeter of the picture = 67.31 cm approximately</u>.
7 0
3 years ago
I need help with this please
Levart [38]
Yu can you think how many triangles fit in that parallelogram? The answer is six. four in the central rectangle and two at the ends, then the area of ​​the parallelogram will be six times greater than that of the triangle in that graph. Good luck! M.
7 0
4 years ago
Explain these questions, please
harina [27]
How I was taught: Make sure both numbers are a fraction. If not put "1" as the denominator. Multiply straight across. Simplify if you can.
3 0
3 years ago
sweaters and hoodies are on sale for the same price at old navy. you buy 4 sweaters and 2 hoodies. you also buy a pair of jogger
horsena [70]

Answer:

$11

Step-by-step explanation:

first you subtract 16 from 82 to get 66. then you divide 66 by 6( the number of sweatshirts and hoodies) and you get $11

7 0
3 years ago
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Evaluate.<br> -|-7 + 3|<br> You
jeka57 [31]

Answer:

<h2> -4 </h2>

Step-by-step explanation:

<em>calculate</em><em> </em><em>the</em><em> </em><em>sum of </em><em>-7</em><em> </em><em>+</em><em> </em><em>3</em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>-|-4|

<em>the</em><em> </em><em>absolute</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>any</em><em> </em><em>number</em><em> </em><em>is </em><em>always</em><em> </em><em>positive</em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>-4</em><em> </em><em> </em><em> </em>

<em> </em><em> </em><em>(</em><em>the</em><em> </em><em>negative</em><em> </em><em>sign</em><em> </em><em>outside</em><em> </em><em>the</em><em> </em><em>absolute</em><em> </em><em>value</em><em> </em><em>signs</em><em> </em><em>is</em><em> </em><em>kept)</em>

8 0
4 years ago
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