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marin [14]
2 years ago
13

Find the measure of an angle between 0º and 360º coterminal with an angle of –110º in standard position

Mathematics
1 answer:
kondor19780726 [428]2 years ago
3 0
<h2>Answer:</h2>

An angle measures how how much you have to rotate one line called <em>initial side</em> so it lies on the top of other line called the <em>terminal side. </em>Angles whose vertex is located at the origin having the initial side on the positive x-axis is said to be in standard position. On the other hand, coterminal angles are angles in standard position having the same terminal side. In this way, for the angle:

-110^{\circ} \\ \\ Its \ coterminal \ is: \\ \\ \alpha=360^{\circ}-110^{\circ}=\boxed{250^{\circ}}

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Answer:

The first one and the last one are true (Since −6 is 6 units to the left of 0, |−6|=6 and −6 is closer to zero on the number line than −7, so |−6|<|−7|.)

Step-by-step explanation:

Absolute value is the distance to zero, and it is always positive. That means the positive and negative versions of a number have the same absolute value. That means the first one is true, and the second and third ones are false. For the last one, -6 is closer to zero, so that means it would be true (The absolute value of -6 is 6, and the absolute value of -7 is 7).

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Evaluate: 3cos 80° cosec 10° + 2 sin 59° sec 31°<br>correct answer will be marked as Brainliest.​
vovangra [49]

Given that

3 cos 80° cosec 10° + 2 sin 59° sec 31°

⇛3 cos(90°-10°) cosec 10°+2 sin (90°-31°) sec 31°

We know that

sin (90° - A) = cos A

cos (90°-A) = sin A

⇛3 sin 10° cosec 10° + 2 cos 31° sec 31°

⇛3 sin 10° (1/sin 10°) + 2 cos 31° (1/cos 31°)

⇛3 (sin 10°/sin 10°) + 2 (cos 31°/cos 31°)

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<u>Answer</u><u>:</u> Therefore, 3cos 80°cosec 10°+2cos 59°sec 31° = 5.

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brainly.com/question/87846?referrer

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