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3 years ago

Someone help me with my algebra homework please

Mathematics

1 answer:

RSB [31]3 years ago

3 0

Answer:

Step-by-step explanation:

x = number of glasses of iced tea

y = number of glasses of lemonade

The total number of glasses is

x + y

The total number of glasses is 44

x + y = 44

This is not a choice, but the answer must be equivalent to this equation.

Solve for x by subtracting y from both sides.

x = 44 - y

Answer: D.

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Oak Street and Elm Street run parallel to each other. When Main Street

____ [38]

Answer:

100degrees

Step-by-step explanation:

From the given diagram;

<2 = <6 (corresponding angle)

Since <6 + 80 = 180

<6 = 180 - 80

<6 = 100 degrees

Since <2 = <6, hence <2 = 100degrees

8 0

3 years ago

Jesse takes two data points from the weight and feed cost data set to calculate a slope, or average rate of change. A ferret wei

fredd [130]

Answer:

$m = 12.33$

Step-by-step explanation:

Given

Ferret:

$Weight = 2.1lb$

$Cost = \$3.40$

Labrador Retriever

$Weight = 70lb$

$Cost = \$7.50$

Required

Determine the slope

Represent the given as x or y

Taking the weight as explanatory variable;

We have:

x = 2.1; y = 3.4

x = 7.5; y = 70

Slope is calculated as:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{70 - 3.4}{7.5 -2.1}$

$m = \frac{66.6}{5.4}$

$m = 12.33$

<em>Hence, the slope is 12.33</em>

7 0

3 years ago

Which choices are equivalent to the expression below? Check all that apply.<br> 5 square root 3

blsea [12.9K]

Option A: $\sqrt{75}$

Option C: $\sqrt{15} \cdot \sqrt{5}$

Option F: $\sqrt{25} \cdot \sqrt{3}$

Solution:

Given expression is $5 \sqrt{3}$ .

Option A: $\sqrt{75}$

$\sqrt{75}=\sqrt{25\times3}$

$=\sqrt{5^2\times3}$

$=5\sqrt{3}$

Hence $\sqrt{75}$ is equivalent expression of $5 \sqrt{3}$ .

Option B: $\sqrt{45}$

$\sqrt{45}=\sqrt{9\times5}$

$=\sqrt{3^2\times5}$

$=3\sqrt{5}$

Hence $\sqrt{45}$ is not equivalent expression of $5 \sqrt{3}$ .

Option C: $\sqrt{15} \cdot \sqrt{5}$

$\sqrt{15} \cdot \sqrt{5}=\sqrt{15\times5}$

$=\sqrt{75}$

$=5\sqrt{3}$ (proved in option A)

Hence $\sqrt{15} \cdot \sqrt{5}$ is equivalent expression of $5 \sqrt{3}$ .

Option D: $\sqrt{3} \cdot \sqrt{5}$

$\sqrt{3} \cdot \sqrt{5}=\sqrt{3\times5}$

$=\sqrt{15}$

Hence $\sqrt{3} \cdot \sqrt{5}$ is not equivalent expression of $5 \sqrt{3}$ .

Option E: 75

75 is a whole number.

Hence 75 is not equivalent expression of $5 \sqrt{3}$ .

Option F: $\sqrt{25} \cdot \sqrt{3}$

$\sqrt{25} \cdot \sqrt{3}=\sqrt{25\times3}$

$=\sqrt{75}$

$=5\sqrt{3}$ (proved in option A)

Hence $\sqrt{25} \cdot \sqrt{3}$ is equivalent expression of $5 \sqrt{3}$ .

Therefore, $\sqrt{75},\ \ \sqrt{15} \cdot \sqrt{5}, \ \ \sqrt{25} \cdot \sqrt{3}$ are all equivalent expressions of $5 \sqrt{3}$ .

6 0

3 years ago

How to solve negative exponents with a negative base?

butalik [34]

The answer would be positive so ignore the negatives.

4 0

4 years ago

I need help with number 7

natali 33 [55]

Answer:

B would be the correct answer

Step-by-step explanation:

5 0

2 years ago