I need help with number 7

Mathematics

1 answer:

natali 33 [55]2 years ago

5 0

Answer:

B would be the correct answer

Step-by-step explanation:

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If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a

harkovskaia [24]

Given:

The function is:

$h(x)=x^2-3x+5$

To find:

The value of $h(2x+1)$ .

Solution:

We have,

$h(x)=x^2-3x+5$

Putting $x=2x+1$ , we get

$h(2x+1)=(2x+1)^2-3(2x+1)+5$

$h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5$

$h(2x+1)=4x^2+4x+1-6x-3+5$

On combining like terms, we get

$h(2x+1)=4x^2+(4x-6x)+(1-3+5)$

$h(2x+1)=4x^2-2x+3$

Therefore, the required function is $h(2x+1)=4x^2-2x+3$ .

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3 years ago

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BartSMP [9]

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3 years ago

Read 2 more answers

Solve 2x+3y=2 5x-y=-29 By elimination

Andreyy89

Answer:

$\huge\boxed{x=-5,\ y=4\to(-5,\ 4)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}2x+3y=2\\5x-y=-29&\text{multiply both sides by 3}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}2x+3y=2\\15x-3y=-87\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad17x=-85\qquad\text{divide both sides by 17}\\.\qquad\dfrac{17x}{17}=\dfrac{-85}{17}\\.\qquad\boxed{x=-5}\\\\\text{Substitute it to the second equation:}\\\\5(-5)-y=-29\\\\-25-y=-29\qquad\text{add 25 to both sides}\\\\-25+25-y=-29+25\\\\-y=-4\qquad\text{change the signs}\\\\\boxed{y=4}$