Given:
The given quadratic polynomial is :

To find:
The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.
Solution:
We have,

Equate the polynomial with 0 to find the zeroes.

Splitting the middle term, we get




The zeroes of the given polynomial are -3 and 4.
The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.
A quadratic polynomial is defined as:




Therefore, the required polynomial is
.
Answer:
BC = 10.24
Step-by-step explanation:
You can use the Pythagoras theorem for this question
+
= 
a = 8cm
b = ???
c = 13cm
We will solve for B (length BC)
+
= 
+
= 
Rearrange for b
=
-
= 105
b = 
b = 10.24
He would need 36 carmel squares to make 2 batches
Answer:
(1/2)x - y = -2
General Formulas and Concepts:
<u>Pre-Alg</u>
<u>Alg I</u>
Slope-Intercept Form: y = mx + b
- m - slope
- b - y-intercept
Standard Form: Ax + By = C
Step-by-step explanation:
<u>Step 1: Define equation</u>
Slope-Intercept Form: 2 + (1/2)x = y
<u>Step 2: Find Standard Form</u>
- Rewrite: y = (1/2)x + 2
- Subtract 1/2x on both sides: y - 1/2x = 2
- Factor negative: -(1/2x - y) = 2
- Divide both sides by -1: 1/2x - y = -2