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rusak2 [61]
4 years ago
15

Please help me it would be greatly appreciated

Mathematics
1 answer:
zvonat [6]4 years ago
6 0

Answer:

a and f

Step-by-step explanation:

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helpppppp nobody does this one either I don’t know whyyyyy
Lisa [10]

Answer:

-6±3i√2

Step-by-step explanation:

First we need to simplify the radical here which is √-288. We can make this i√288, and then further simplify by taking out 12 giving us 12i√2. Now we have

-24±12i√2/4

From here we just divide all the terms in the numerator by 4 and get -6±3i√2

6 0
3 years ago
So I'm doing Flvs and i need help to understand the difference between the answers to this question
kakasveta [241]
I think I know what you are thinking and you are halfway on the right track. : ) You are probably looking at the x-axis right in between the pentagon and its reflection. This <em />is the right line, but it is a y-line and not x. When we say a line is at x = 0, we mean that every point on that line has an x-value of 0, such as (0,1), (0,2), (0, 3) etc. Any line in the form x = 0 (or any other number) is a vertical line. Y-lines are the same way but they run horizontal like the line of reflection in this problem.        : )
4 0
4 years ago
4m2 - 3mm + 5m4<br> help??
Alina [70]

Answer:

612mm I believe

5 0
3 years ago
Please Help Me ASAP I Need <br> This For My grade
Helga [31]
D would be your answer. Since the x is negative the graph is decreasing and -3 is you y-intercept
6 0
3 years ago
A landscaper has enough cement to make a patio with an area of 150 Sq ft. The homeowner wants the length of the patio to be 6 ft
Natasha_Volkova [10]
A=lw=150\\l=w+6\\(w+6)w=150\\w^2+6w=150\\w^2+6w-150=0\\w=\frac{-b+-\sqrt{b^2-4ac}}{2a}\\w=\frac{-(6)+-\sqrt{(6)^2-4(1)(-150)}}{2(1)}\\w=\frac{-6+-\sqrt{36+600}}{2}\\w=\frac{-6+-\sqrt{636}}{2}\\w=\frac{-6+-2\sqrt{159}}{2}\\w=-3+-\sqrt{159}>0\\w=-3+\sqrt{159}\\\\l=(-3+\sqrt{159})+6\\l=3+\sqrt{159}

Width = -3 + sqrt(159)
Length = 3 + sqrt(159)
4 0
3 years ago
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