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sveta [45]
3 years ago
15

Sarah needs 3 cups of sugar to make two dozen cookies. how much sugar does she need to make 12 dozen cookies

Mathematics
2 answers:
UNO [17]3 years ago
8 0

Answer:

Step-by-step explanation:

she  n

guapka [62]3 years ago
5 0

the answer is 9 cups of augar

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An amount of 1,500.00 is deposited in a bank paying an annual interest rate of 4.3% compounded quarterly. What is the balance af
defon

First, multiply the 1,500 by 4.3% to come up with $64.50 every three months (the question says compounded quarterly).

$64.50 x 4(quarters in a year) = $258.00 per year

$258.00 x 6 years = $1,548.00

$1,500.00 + $1,548.00 = $3,048.00 balance after six years


8 0
3 years ago
P = 0.5e - 5 to determine P
ipn [44]

Answer:

Let's solve your equation step-by-step.

p=(0.5)(2.718282)−5

Step 1: Simplify both sides of the equation.

p=(0.5)(2.718282)−5

p=1.359141+−5

p=(1.359141+−5)(Combine Like Terms)

p=−3.640859

p=−3.640859

Answer:

p=−3.640859

Step-by-step explanation:

6 0
3 years ago
Point D is on line segment \overline{CE}
ANTONII [103]

Answer:

DE = 18

Step-by-step explanation:

Given that,

Point D is on line segment CE.

DE = x+10, CD=6 and CE=3x

We need to find the length of DE.

ATQ,

CE = CD + DE

Putting all the values,

3x = 6 + x+10

Taking like terms together

3x-x = 16

2x = 16

x = 8

DE = x+10

= 8+10

= 18

Hence, the length of DE is 18.

5 0
3 years ago
There are 48 different animals pictured in Jorge's book. If 1/3 of them are herbivores how many herbivores?
Stolb23 [73]
16. 48 divided by 3 is 16
8 0
3 years ago
Read 2 more answers
A) If the 5th term of an A.P. is double the 7th term, show that the sum of the 17 terms zero.​
gayaneshka [121]

Answer:

see explanation

Step-by-step explanation:

The nth term of an AP is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₅ is double a₇ , then

a₁ + 4d = 2(a₁ + 6d) , that is

a₁ + 4d = 2a₁ + 12d ( subtract a₁ from both sides )

4d = a₁ + 12d ( subtract 12d from both sides )

- 8d = a₁

The sum of n terms of an AP is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , substitute values

S_{17} = \frac{17}{2} ( 2(- 8d) + 16d)

     = 8.5(- 16d + 16d)

     = 8.5 × 0

     = 0

5 0
3 years ago
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