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Mnenie [13.5K]
3 years ago
7

The U.S. Federal Seed Act establishes germination rates for various fruit and vegetable seeds. Watermelon seeds are to meet a 70

% germination standard. A skeptical gardener who has not had very good luck planting watermelons believes that the seed company he purchases seeds from is not adhering to the 70% federal mandate. Once a week for 12 weeks, he purchases a pack of 10 watermelon seeds to act as his sample. He plants the seeds in a greenhouse with good soil to maintain a consistent temperature and watering routine. He finds that the germination rate for the company's watermelon seeds is 55%. Is this convincing evidence that the proportion of watermelon seeds that germinate is less than 70%
Mathematics
1 answer:
babymother [125]3 years ago
7 0

Answer:

Following are the responses to the given question:

Step-by-step explanation:

Level of Significance,\alpha =    0.05

Sample Size, n =    120          

Sample Proportion,   \hat{P} = 0.600      

z -value =   Z_{\frac{\alpha}{2}} =  1.960  \ \  [excel formula =NORMSINV(\frac{\alpha}{2})]

Standard ErrorSE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} =    0.0447        

margin of error E = Z\times SE =    1.960   \times   0.0447   =   0.0877

When 95\% Confidence Interval              

Interval Lower Limit= \hat{p} - E =    0.600   -   0.0877   =   0.5123

Interval Upper Limit =\hat{p}+ E =   0.600   +   0.0877   =   0.6877

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How do I Simplify i^54
yanalaym [24]

Answer:

i^{54}=-1

Step-by-step explanation:

First, recall the 4 basic imaginary exponents:

i^1=i \text{, }i^2=-1\text{, }i^3=-1\text{ and } i^4=1

So, we want to find:

i^{54}

This is the same as:

=i^{52}\cdot i^2

52 is 4 times 13. Thus:

=(i^4)^{13}\cdot i^2

Since we know that i to the fourth is 1:

=(1)^{13}\cdot i^2

Simplify:

=i^2

And this equals:

=-1

So:

i^{54}=-1

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