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4 years ago

A rug covers 79 square feet of the floor. What is the approximate length of one side of the rug

Mathematics

1 answer:

sesenic [268]4 years ago

4 0

The best and most correct answer among the choices provided by the question is sqrt(79) or 8.89 feet.

Hope my answer would be a great help for you

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Find x Help me plz!!!

mariarad [96]

9514 1404 393

Answer:

x = 8

Step-by-step explanation:

Assuming the figure is a parallelogram, the diagonals bisect each other. That means ...

3x -11 = x +5

2x = 16 . . . . . . . add 11-x to both sides

x = 8 . . . . . . divide by 2

3 0

3 years ago

Read 2 more answers

( 2 7/8 + 3 3/8 ) + 1 1/8 =

Monica [59]

Look at the attached picture⤴

Hope this will help u...

5 0

3 years ago

Due Soon Need Help Geometry!

AveGali [126]

Some basic formulas involving triangles

\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa 2 =b 2+2 + c 2

−2bc cos α

\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab 2=

m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m b2 = 41(2a 2 + 2c 2-b 2)

Bisector formulas

\ \frac{a}{b} = \frac{m}{n} ba =nm

\ l^2 = ab - mnl 2=ab-mm

A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=

\ A = \sqrt{p(p - a)(p - b)(p - c)}A=

p(p−a)(p−b)(p−c)

\iits whatever A = prA=pr with r we denote the radius of the triangle inscribed circle

\ A = \frac{abc}{4R}A=

abc

- R is the radius of the prescribed circle

\ A = \sqrt{p(p - a)(p - b)(p - c)}A=

p(p−a)(p−b)(p−c)

5 0

3 years ago

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 3x2 − 2x + 1, [0, 2] Yes, it do

expeople1 [14]

Answer:

Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable

Step-by-step explanation:

We are given the Function

f(x) = $3x^2 -2x +1$

The two basic hypothesis of the mean valued theorem are

The function should be continuous in [0,2]

The function should be differentiable in (1,2)

upon checking the condition stated above on the given function

f(x) is continuous in the interval [0,2] as the functions is quadratic and we can conclude that from its graph

also the f(x) is differentiable in (0,2)

f'(x) = 6x - 2

Now the function satisfies both the conditions

so applying MVT

6x-2 = f(2) - f(0) / 2-0

6x-2 = 9 - 1 /2

6x-2 = 4

6x=6

x=1

so this is the tangent line for this given function.

4 0

3 years ago

What is the product of (-a + 3)(a + 4)?

spayn [35]

Answer: The product of (-a + 3)(a + 4) is: -a^2-a+12

Step-by-step explanation:

(-a+3)(a+4) = -a*a-a*4+3*a+3*4

=-a^{2} -4a+3a+12

now just simply combine..

=-a^2-a+12

the answer is -a^2-a+12

8 0

3 years ago