A gaming console that is $300 plus 8% tax. What is the final cost of the console? (Round to nearest cent)

Imagine the United States only had two postage stamps, a 3 cent stamp and a 7 cent stamp. If you can put any number of stamps on

cricket20 [7]

Answer:

not possible: 1, 2, 4, 5, 8, 11
possible: all others

Step-by-step explanation:

Obviously, all multiples of 3 and 7 can be paid.

1 cent can be added by adding a 7-cent stamp and taking away two 3-cent stamps. 2 cents can be added by adding three 3-cent stamps and taking away one 7-cent stamp. Hence any value more than 7 +2(3) = 13 cents can always be accommodated.

Amounts that are impossible:

1, 2, 4, 5, 8, 11 cents

All other positive integer amounts are possible.

7 0

3 years ago

Please help quick i get brainliest

IrinaK [193]

Question 1:
If you know that 3 squares equals 7 circles and the squares are being counted by 3, then continue to count the circle by 3 until you get 25 circles.
Example:
3 Squares : 7 circles
4 squares : 10 circles
5 squares : 13 circles
6 squares : 16 circles
7 squares : 19 circles
8 squares : 22 circles
9 squares : 25 circles Add 9 squares to 3 = 12
You will have 12 squares when continues to count all the way to 25 circles.

Question 2:
Just multiply 14 by 28 and you will get your answer. Which is 3. The missing digit's 3. You can then check by doing 392 ÷ 14 to see if you get 28.

6 0

2 years ago

How would you find the quadratic that goes through the point (4,0), the axis of symmetry is x=7, and it also goes through the po

nasty-shy [4]

9514 1404 393

Answer:

y = (5/27)(x -7)^2 -5/3

Step-by-step explanation:

Use the given points to find the unknowns in the equation.

If the axis of symmetry is x=7, then the equation can be written in the form ...

y = a(x -7)^2 +b

Filling in the two point values, we have two equations:

0 = a(4 -7)^2 +b ⇒ 9a +b = 0

5 = a(1 -7)^2 +b ⇒ 36a +b = 5

__

Subtracting the first equation from the second, we have ...

(36a +b) -(9a +b) = (5) -(0)

27a = 5

a = 5/27

Substituting that value into the first equation gives ...

9(5/27) +b = 0

5/3 +b = 0

b = -5/3

So, the quadratic can be written in vertex form as ...

y = (5/27)(x -7)^2 -5/3

4 0

2 years ago

The equations 2 x minus y = negative 2, 3 x + 2 y = 5, 4 x minus y = 2, and 22 x + 10 y = 7 are shown on the graph below. On a c

KiRa [710]

Answer:

The correct answer is First option:

$22x+10y=7\\ 2x-y=-2$

Step-by-step explanation:

We are given 4 equations:

$22x+10y=7\\ 2x-y=-2\\3x+2y=5\ and\ \\4x-y=2$

Let us solve the first two:

$22x+10y=7...... (1)\\ 2x-y=-2 ...... (2)$

Multiplying (2) with 10 and adding to (1):

$22x+20x=7-20\\\Rightarrow 42x=-12\\\Rightarrow x = -0.2857 \approx -0.3$

So, approximately, value of x is -0.3.

Putting value of x in (2):

$2 \times -0.3 - y =-2\\\Rightarrow y = -0.6+2\\\Rightarrow y = 1.4$

value of x is approximately -0.3 so y is approximately 1.4.

So, the solution is $\approx$ (–0.3, 1.4)

The correct answer is First option:

$22x+10y=7\\ 2x-y=-2$

The above two equations have a solution approximately (–0.3, 1.4).

3 0

2 years ago

Read 2 more answers

Which sequence is geometric and has 1/4 as its fifth term and 1/2 as the common ratio?

olchik [2.2K]

5th term = a1r^4 where a1 = first term and r = common ratio

so 1/4 = a1 * (1/2)^4

a1 = 1/4 / (1/2)^4 = 4

so the sequence is 4 , 4*1/2, 4*(1/2)^2...

= 4, 2, 1, 1/2, 1/4 .....

5 0

2 years ago

Read 2 more answers