Solve. 3x2 + 4x = –5
using quadratic equation ...?
1 answer:
3x^2 + 4x - 5 = 0
x = [-b ±√(b^2 - 4ac)]/2a
a = 3
b = 4
c = -5
x = [-4 ±√(16 + 60)]/6
x = [-4 ±√76]/6
x = [-4 ±√(2^2 * 19)]/6
x = [-4 ±2√19]/6
x = [-2 ±√19]/3
x = [-2 + √19]/3
x = [-2 + 4.35]/3
x = 2.35/3
x = 0.78 (rounded to the nearest hundredth)
x = [-2 - ±√19]/3
x = [-2 - 4.35]/3
x = -6.35/3
x = -2.12 (rounded to the nearest hundredth)
<span>∴ x = -2.12 , 0.78 (rounded to the nearest hundredth)</span>
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