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3 years ago

A fish swims at 10 ft below sea level, and then swims another

Mathematics

2 answers:

nevsk [136]3 years ago

8 0

Answer20+20=40

Step-by-step explanation:

jasenka [17]3 years ago

3 0

10ft+ 10ft= 20ft
The fish swam 20 ft deeper to avoid the shark

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Please help with this math problem

dlinn [17]

I think it’s a I’m not really sure but I think

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3 years ago

The graph below shows a quadratic function f(x) and an absolute value function g(x)

Sophie [7]

Answer:

The x-values that are approximate solution of the equation $f(x) = g(x)$ are $x_{1} \approx -3.5$ and $x_{2}\approx 5$ , respectively.

Step-by-step explanation:

From graph we infer that the x-values that represents a solution to the system of equations corresponds to those values of x in which both functions coincide. As we see, there are two x-values for $f(x) = g(x)$ , which are described below:

$x_{1} \approx -3.5$ and $x_{2}\approx 5$

The x-values that are approximate solution of the equation $f(x) = g(x)$ are $x_{1} \approx -3.5$ and $x_{2}\approx 5$ , respectively.

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4 years ago

it is given that ln(y+1) - ln(y) = 1+3ln(x) . express y in terms of x in a form not involving logarithms

Rina8888 [55]

$ln( \frac{y + 1}{y} ) = ln( {x}^{3} e) \\ \frac{y + 1}{y} = {x}^{3} e$

4 0

4 years ago

Type the correct answer in the box.

Iteru [2.4K]

9514 1404 393

Answer:

b2 = 2A/h -b1

Step-by-step explanation:

The usual formula for the area of a trapezoid is ...

$A=\dfrac{1}{2}(b_1+b_2)h$

We can solve this for b2:

$\dfrac{2A}{h}=b_1+b_2 \qquad\text{multiply by $\dfrac{2}{h}$}\\\\ \dfrac{2A}{h}-b_1=b_2 \qquad\text{subtract $b_1$}\\\\ \boxed{b_2=\dfrac{2A}{h}-b_1}$

3 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=10x%2B2%3D32" id="TexFormula1" title="10x+2=32" alt="10x+2=32" align="absmiddle" class="latex-

Sunny_sXe [5.5K]

3 would represent x.
10 times 3 = 30
30 plus 2 = 32
hope this helps!

3 0

3 years ago

Read 2 more answers