The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Answer:
Hi, there the answer is (4,2)
Step-by-step explanation:
The reason is that 4 is the y-axis and 2 is the x-axis and
the rule is x is first then y
The correct format for writing this it is supposed to be (2,4).
Therefore, your answer will (4,2)
Answer:
Step-by-step explanation:
approximately 0.94625 liters per second
It is 3 how many different outcomes are they there are three outcomes road once
Account balance is $123.08
Step-by-step explanation:
- Step 1: Balance in Thompson's account = $283.12. Calculate the total amount of checks Thompson wrote in the month.
Total amount of checks = $23.09 + $7.56 + $125.11 + $4.28
= $160.04
- Step 2: Calculate his balance.
Account balance = $283.12 - $160.04
= $123.08