Answer:
0,5
Step-by-step explanation:
Answer:
x = -7
Step-by-step explanation:
Recall this rule of exponents:
a^b*a^c = a^(b+c)
We have:
6^9*6^x = 6^2
Then 9 + x = 2. Subtracting 9 from both sides, we get: x = -7
Part A:
Let the width of the rectangle be = x inches
As given, the length of a rectangle is 3 more inches than the width so let the length of the rectangle be = x+3 inches
Perimeter is given as = 54 inches
Perimeter = 
Equation becomes:
=54
Part B:
Solving the equation we get
Hence, the width of the rectangle is 12 inches
Length = x+3 = 12+3 = 15 inches
Hence, length of the rectangle is 15 inches.
complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
<span>
<span>
</span>
2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
</span><span>
<span>
</span>
3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
</span><span>
<span>
</span>
4. complete the squre and expand
</span>
so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
