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3 years ago

Help .........................................

Mathematics

1 answer:

sergeinik [125]3 years ago

7 0

Answer:

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Step-by-step explanation:

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Simplify and write the trig expression in terms of sin and cos

dsp73

We have:

$cot(-x)cos(-x)+sin(-x)=-\frac{1}{f(x)}$

Then we use trigonometric identities to change the negative sign of the trigonometric functions, so:

$-sin(x)-cot(x)cos(x)=-\frac{1}{f(x)}$

We clear f(x):

$f(x)=\frac{1}{sin(x)+cot(x)cos(x)}=\frac{1}{sin(x)+\frac{cos(x)}{sin(x)}cos(x)}=\frac{1}{sin(x)+\frac{cos^2(x)}{sin(x)}}$

we simply what we can:

$f(x)=\frac{1}{\frac{sin^2(x)+cos^2(x)}{sin(x)}}=sin(x)$

Thus, the correct answer is;

$f(x)=sin(x)$

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1 year ago

A water tank holds 18,000 gallons. How long will it take for the water level to reach 6,000 gallons if the water is used at an a

astraxan [27]

It will take 13.33 days to fill it to 6,000 gallons.

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3 years ago

Please help this is due and i only got the second part done

Ainat [17]

Answer:2n+13=75 n=31

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3 years ago

A woman walks due west on the deck of a ship at 3 mi/h. The ship is moving north at a speed of 22 mi/h. Find the speed and direc

Minchanka [31]

Answer: The speed is 22.2 mi/hr and woman is 8° north relative to the surface of the water.

Step-by-step explanation:

Since we have given that

Speed at which woman walks due west = 3 mi/hr

Speed at which ship moving due north = 22 mi/hr

Now it forms "Pythagorus theorem":

So, it becomes,

$H^2=B^2+P^2\\\\H^2=3^2+22^2\\\\H^2=9+484\\\\H^2=493\\\\H=\sqrt{493}\\H=22.20\ mi/hr$

And the direction of the woman relative to the surface of the water is given by

$\theta=\sin^{-1}x(\dfrac{3}{22.2})=7.76\approx 8^\circ$

Hence, the speed is 22.2 mi/hr and woman is 8° north relative to the surface of the water.

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3 years ago

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Alecsey [184]

1/12 is the answer i think

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3 years ago