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3 years ago

Help .........................................

Mathematics

1 answer:

sergeinik [125]3 years ago

7 0

Answer:

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Step-by-step explanation:

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Help ASAp 3mins left

IRINA_888 [86]

You didn’t attach anything?..

4 0

3 years ago

Read 2 more answers

G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =

laiz [17]

Given:

The two functions are:

$g(b)=5b-9$

$h(b)=(b-1)^2$

To find:

The value of $(h\circ g)(-6)$ .

Solution:

We have,

$g(b)=5b-9$

$h(b)=(b-1)^2$

We know that,

$(h\circ g)(b)=h(g(b))$

$(h\circ g)(b)=h(5b-9)$

$(h\circ g)(b)=[(5b-9)-1]^2$

$(h\circ g)(b)=[5b-10]^2$

Putting $b=-6$ , we get

$(h\circ g)(-6)=[5(-6)-10]^2$

$(h\circ g)(-6)=[-39-10]^2$

$(h\circ g)(-6)=[-49]^2$

$(h\circ g)(-6)=2401$

Therefore, the value of $(h\circ g)(-6)$ is 2401.

7 0

3 years ago

PLEASE HELP I've been struggling on this one :(

In-s [12.5K]

Answer: The answer is (x+2)(x-4)(x-4)
Or as a short form you can write it as $(x+2) (x-4)^{2}$

Step-by-step explanation:

Answer is very lengthy but I am 100% sure that's the correct answer

6 0

1 year ago

Read 2 more answers

Alaina is selling wreaths and poinsettias for her chorus fundraiser. Wreaths cost $27 each poinsettia cost $20 each. If she sold

marishachu [46]

Answer:

The number of wreaths Alaina sells is 9 .

Step-by-step explanation:

As given

Alaina is selling wreaths and poinsettias for her chorus fundraiser.

Wreaths cost $27 each poinsettia cost $20 each.

If she sold 15 poinsettias and made $543.

Let us assume that the number of wreaths Alaina sells = x

As the number of poinsettias Alaina sells = 15

Than the equation becomes

27x + 15 × 20 = 543

27x + 300 = 543

27x = 543 - 300

27x = 243

$x = \frac{243}{27}$

x = 9

Therefore the number of wreaths Alaina sells is 9 .

4 0

3 years ago

A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o

balu736 [363]

Answer:

$P(X \ge 1) = 0.509$

$P(X \ge 1) = 0.6807$

Step-by-step explanation:

From the question we are told that

The number of students in the class is N = 20 (This is the population )

The number of student that will cheat is k = 3

The number of students that he is focused on is n = 4

Generally the probability distribution that defines this question is the Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally probability mass function is mathematically represented as

$P(X = x) = \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}$

Here C stands for combination , hence we will be making use of the combination functionality in our calculators

Generally the that he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

Here

$P(X \le 0) = \frac{ ^{3} C_0 * ^{20 - 3} C_{4- 0}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ ^{3} C_0 * ^{17} C_{4}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ 1 * 2380}{ 4845}$

$P(X \le 0) = 0.491$

Hence

$P(X \ge 1) = 1 - 0.491$

$P(X \ge 1) = 0.509$

Generally the that he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

$P(X \ge 1) =1- [ \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]$