Hello :
the tangent has same slope of the line 16x -y +5 = 0 because parallel.
y = 16x + 5
the slope is : 16
but : f'(x) = 16
f'(x) = 16x^3 - 16x +16
solve : 16x^3 - 16x +16 = 16
x^3 - x +1 =1
x^3 - x = 0
x(x² - 1 ) =0
x(x -1 )(x +1) =0
x=0 or x-1 =0 or x +1= 0
x=0 or x = 1 or x = -1
if : x = 0 : y = 4(0)^4 -8(0)^2+16(0) +7 =7
if : x =1 : y = 4(1)^4 -8(1)^2+16(1) +7 = 19
if : x = -1 : y = 4(-1)^4 -8(-1)^2+16(-1) +7 = -13
<span>the points : A(0,7) , B(1 , 19) , c ( -1 , -13)</span>
Answer:
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Answer:
17/15
Step-by-step explanation:
Find the GCF of the denominators
15
Convert the fractions
1/3 ---> 5/15
4/5 ---> 12/15
Add.
12/15 + 5/15 = 17/15
-7 -14(1/7)
remove parenthesis
14 * 1/7 = 2 (14/1 * 1/7 = 2/1 which we reduce to just 2)
-7 -2
-9
Since none of the terms have the same variables the like terms would be (A) because they are both constants
